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Dennis_Churaev [7]
3 years ago
8

How would i find this missing number?

Mathematics
2 answers:
Likurg_2 [28]3 years ago
5 0

Answer:

You would count by 2s i assume by how the graph is plotted so the next number should be 5

Step-by-step explanation:

liq [111]3 years ago
3 0

Answer: 2

Step-by-step explanation:

You might be interested in
Which phrase matches the expression c^3
Yuliya22 [10]

Answer:A

Step-by-step explanation:

Think about it as a process of elimination.

It can't be "B' for the simple fact that "increased by'' is a term that is often used for addition problems.

It can't be "C" because, as previously stated, sum is a term that is used in addition problems.

It can't be "D" because this is a unit that you are using.

4 0
3 years ago
What's 7/8x4/5? Cmon peeps it's hard
Alik [6]
\frac{7}{8}* \frac{4}{5}= \frac{28}{40} =\boxed{0.7}\ or\ \boxed{ \frac{7}{10}}
5 0
3 years ago
Read 2 more answers
At the beginning of the week, James stopped by a local grocery store to buy fruit. He bought five bananas and three pears at a t
suter [353]
Lets try to solve this problem using 2 equations, also,we will have bananas=b and pears =p

5b+3p= $3.80
2b+4p= $3.20  i will divide this equation by 2 and get
b+2p= $ 1.60  we subtract 2p from both side so i can find the cost for 1 banana
b+2p-2p=1.60-2p
b= $1.60-2p

I will replace the b in the first equation now,

5(1.60-2p)+3p=$3.80
8-10p+3p=3.80   solving for p
8-7p=3.80     we subtract 8 from both sides
-7p=-8+3.80
-7p=-4.20  we multiply both sides by (-1)
7p=4.20  we divide now both sides by 7
p=0.60   a pear cost 0.60 cents

a banana is b=1.60-2p,   b=0.40 cents



4 0
3 years ago
PLEASE HELP, ILL GIVE YOU 20 POINTS!!!
Troyanec [42]

Answer:

-2,4

Step-by-step explanation:

i think

5 0
3 years ago
Read 2 more answers
The savings account offering which of these APRs and compounding periods
Ann [662]

Answer:

The answer is "Option C"

Step-by-step explanation:

The using formula= (1+\frac{r}{n})^n -1

→r = rate

→ n = compounded value

In choice a:

When compounded is monthly 4.0784\%  

n = 12

\to (1+ \frac{0.040784}{12})^{12} = 1.0403-1 = 0.0403

In choice b:

When compounded is quarterly4.0792\%

n = 3\\\\\to (1+ \frac{0.040792}{12} )^{3} = 1.0102-1 = .0102

In choice c:

Whenn compounded is daily 4.0730 \%

n = 365\\\\\to (1+ \frac{0.040730}{12})^{365}  = 3.328-1 = 2.328

In choice d:

When compounded is semiannually4.0798\%

n = 2\\\\\to (1+ \frac{0.040798}{12})^{2} = 1.0066-1 = 0.0066

7 0
2 years ago
Read 2 more answers
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