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Sidana [21]
3 years ago
7

30. Quickly now, what is the sum of all integers from 1 to 100?.

Mathematics
2 answers:
Elena-2011 [213]3 years ago
6 0

Answer:

5050

Step-by-step explanation:

grandymaker [24]3 years ago
4 0

Answer:

5050

Step-by-step explanation:

Natural numbers from 1 to 100 is a set of the first 100 natural numbers, with 1 as the natural number and 100 as the largest one. Natural numbers being part of the number system includes all the positive integers from 1 to infinity. These are also called counting numbers as they do not include zero or negative numbers. The set of natural numbers is a classification under the bigger set of real numbers including only the positive integers, but not zero, fractions, decimals, and negative numbers.

The natural numbers from 1 to 100 can be written as 1, 2, 3, 4,5…….100 is an arithmetic progression (A.P). The sum of all natural numbers 1 to 100 can be calculated using the formula, S= n/2[2a + (n − 1) × d], where n is the total number of natural numbers from 1 to 100, d is the difference between the two consecutive terms, and a is the first term. There are a total of 100 natural numbers, so n = 100.

Thus, a = 1, d = 1 and n = 100

Let's calculate the sum of the natural numbers 1 to 100

The sum of an A.P,

S = n/2[2a + (n − 1) × d]

S = 100/2[2 + (100 – 1) × 1]

S = 50 [2 + 99]

S = 5050

Therefore, the sum of natural numbers from 1 to 100 is 5050.

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3 years ago
Suppose lightning strikes at an average of 1.4 strikes per minute during a particular storm. You play the following game: if the
ZanzabumX [31]

Answer:

$3.25

Step-by-step explanation:

Given that:

Mean, λ = 1.4

Strike within next minute = $3 won

Strike between one and 2 minutes = $5

Strike more than 2 minutes = $1

Probability that next strike occurs within the next minute :

Using poisson :

P(x < 1) = 1 - e^-(λx) ;

P(x < 1) = 1 - e^-(1.4*1) = 1 - e^-1.4

P(x < 1) = 1 - 0.2465969

P(x < 1) = 0.7534030

Next strike occurs between 1 and 2 minutes :

(1 < x < 2) :

P(x < 2) - P(x < 1)

P(x < 2) = 1 - e^-(λx) ;

P(x < 2) = 1 - e^-(1.4*2) = 1 - e^-2.8

P(x < 2) = 1 - 0.0608100

P(x < 2) = 0.9391899

P(x < 2) - P(x < 1)

0.9391899 - 0.7534030 = 0.1857869

P(striking after 2 minutes)

P(x > 2) = e^-(λx) ;

P(x > 2) = e^-(1.4*2) = e^-2.8

P(x > 2) = 0.0608100

Amount charged :

(0.7534030 * 3) + (0.1857869 * 5) + (0.06081 * 1)

= 3.2499

= $3.25

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3 years ago
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