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Marrrta [24]
3 years ago
6

Simplify this please. (29)^3

Mathematics
2 answers:
bagirrra123 [75]3 years ago
8 0

Hey!

················································

Simplify:

29^3

················································

Solution:

29^3 = 29 x 29 x 29

29 x 29 x 29 = 24,389

················································

Answer:

24,389

················································

Hope This Helps :)

Effectus [21]3 years ago
3 0

Answer:

24,389

Step-by-step explanation:

29x29x29

29x29=841 841x29=24,389

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Devaughn is 8 years older than Sydney. The sum of their ages is 64. What is Sydney's age?
Zigmanuir [339]

Answer:

Sydney's age is 28

Step-by-step explanation:

Let Devaughn be D

And Sydney be S

D=S+8..... equation 1

D+S=64...... equation 2

Substitute equation 1 to equation 2

S+8+S=64

2S+8=64

2S=64-8

2S=56

S=56/2

S=28

Hope it helps

Good luck

8 0
3 years ago
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Aleonysh [2.5K]

Answer: you got this smarty!!!

Step-by-step explanation:

5 0
2 years ago
When functions are defined by more than one​ equation, they are called?
USPshnik [31]
When functions are defined by more than one equation, they are called piecewise- defined functions.

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3 years ago
C ÷ -3 = 8 I’ve been stuck on this prob for awhile and I need help on it
Otrada [13]
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8 0
3 years ago
An important problem encountered by personnel directors and others faced with the selection of the best in a finite set of eleme
SVETLANKA909090 [29]

Answer:

1.63% probability that the 10 selected include include all the best 5 engineers in the group of 20

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the engineers are selected is not important, so the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes:

10 engineers selected from a set of 20.

5 best, from a set of 5.

Other 5, from a set of 20-5 = 15.

D = C_{5,5}*C_{15,5} = \frac{5!}{5!(5-5)!}*\frac{15!}{5!(15-5)!} = 3003

Totao outcomes:

10 engineers selected from a set of 20.

T = C_{20,10} = \frac{20!}{10!(20-10)!} = 184756

Probability:

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1.63% probability that the 10 selected include include all the best 5 engineers in the group of 20

5 0
3 years ago
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