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3 years ago

Which of these shapes are quadrilaterals? Choose ALL the correct answers.

Mathematics

1 answer:

kherson [118]3 years ago

3 0

Answer:

The red square, the green rectangle, the pink rhombus, and the green trapezoid.

Step-by-step explanation:

A quadrilateral is a shape that has 4 sides so all you have to do is count how many sides the shape has.

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11, 1/12 siplfied plz hury

Ber [7]

Answer:uhmmmmmmmmmmmmmm

Step-by-step explanation:

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3 years ago

ABCD is a rhombus. If AC = 8 cm and BC = 6 cm, what is the area of the rhombus?

anygoal [31]

Answer:24, it depend upon the picture

Step-by-step explanation:

if the ac and bc are diagonals the area of rhombus equal to 24.because area of the rhombuss = pq/2where p and q are the diagonals

7 0

3 years ago

Change 5 5/16 into a decimal and show work

Alex Ar [27]

to convert a fraction to a decimal, like say a/b is really simply the quotient of a ÷ b.

now, let's first convert the mixed fraction to improper, and then do the division.

$\bf \stackrel{mixed}{5\frac{5}{16}}\implies \cfrac{5\cdot 16+5}{16}\implies \stackrel{improper}{\cfrac{85}{16}}\\\\[-0.35em] \rule{31em}{0.25pt}\\\\ \cfrac{85}{16}\implies 85\div 16\implies 5.3125$

3 0

4 years ago

Find the slope and y intercept of the line whose equation is -6x+y=-4

Ad libitum [116K]

For
ax+by=c
slope=-a/b

we have
-6x+1y=-4
slope=-6/-1=6
slope is 6

yint is where x=0

-6(0)+y=-4
0+y=-4
y=-4
yint is at y=-4 or (0,-4)

8 0

3 years ago

The student population at the University is currently 400. The expected annual rate of increase is predicted to be 0.02. What wi

kotegsom [21]

Answer:

The population of the students at the University after 5 years is <u>442</u>.

Step-by-step explanation:

Given:

Current population of students is, $P_o=400$

Growth rate is, $r=0.02$

Time after which population is needed is, $t=5\ years$

Let 'P' be the population after 't' years.

Population growth is an exponential growth and the equation to determine the population after 't' years is given as:

$P=P_oe^{rt}$

Now, plug in 400 for $P_o$ , 0.02 for 'r', 5 for 't' and solve for 'P'. This gives,

$P=(400)e^{0.02\times 5}\\\\P=400\times e^{0.1}\\\\P=400\times 1.1052\\\\P=442$

Therefore, the population of the students at the University after 5 years is 442.

8 0

3 years ago