Answer:
Step-by-step explanation:
(-6 , 4) & (-1 , 2)
Slope = 
![= \frac{2-4}{-1-[-6]}\\\\= \frac{-2}{-1+6}\\\\= \frac{-2}{5}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B2-4%7D%7B-1-%5B-6%5D%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-2%7D%7B-1%2B6%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-2%7D%7B5%7D)
m = -2/5 & (-6 , 4)
y -y1 = m(x -x1)
![y - 4 = \frac{-2}{5}(x - [-6])\\\\y - 4 = \frac{-2}{5}(x + 6)\\\\y - 4 = \frac{-2}{5}x + 6*\frac{-2}{5}\\\\y = \frac{-2}{5}x -\frac{12}{5}+4\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{4*5}{1*5}\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{20}{5}\\\\y=\frac{-2}{5}x+\frac{8}{5}](https://tex.z-dn.net/?f=y%20-%204%20%3D%20%5Cfrac%7B-2%7D%7B5%7D%28x%20-%20%5B-6%5D%29%5C%5C%5C%5Cy%20-%204%20%3D%20%5Cfrac%7B-2%7D%7B5%7D%28x%20%2B%206%29%5C%5C%5C%5Cy%20-%204%20%3D%20%5Cfrac%7B-2%7D%7B5%7Dx%20%2B%206%2A%5Cfrac%7B-2%7D%7B5%7D%5C%5C%5C%5Cy%20%3D%20%5Cfrac%7B-2%7D%7B5%7Dx%20-%5Cfrac%7B12%7D%7B5%7D%2B4%5C%5C%5C%5Cy%3D%5Cfrac%7B-2%7D%7B5%7Dx-%5Cfrac%7B12%7D%7B5%7D%2B%5Cfrac%7B4%2A5%7D%7B1%2A5%7D%5C%5C%5C%5Cy%3D%5Cfrac%7B-2%7D%7B5%7Dx-%5Cfrac%7B12%7D%7B5%7D%2B%5Cfrac%7B20%7D%7B5%7D%5C%5C%5C%5Cy%3D%5Cfrac%7B-2%7D%7B5%7Dx%2B%5Cfrac%7B8%7D%7B5%7D)
Answer:
see explanation
Step-by-step explanation:
(1)
Given
g(r) = (r + 14)² - 49
To obtain the zeros, let g(r) = 0 , that is
(r + 14)² - 49 = 0 ( add 49 to both sides )
(r + 14)² = 49 ( take the square root of both sides )
r + 14 = ± 
= ± 7 ( subtract 14 from both sides )
r = - 14 ± 7, then
r = - 14 - 7 = - 21 ← smaller r
r = - 14 + 7 = - 7 ← larger r
(2)
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
g(r) = (r + 14)² - 49 ← is in vertex form
with vertex = (- 14, - 49 )
If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangle<span>ABC.
</span>If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangleABC.
<u>Corrected question :</u>
Solve the equation. Write your answer as an integer or simplified fraction.
<u>Required Solution :</u>
The given equation,
★ Multiplying -7 into (n - 2),
>> 8n - 7 × (n - 2) = 18
>> 8n - 7n + 14 = 18
★ On substracting 7n from 8n we gets,
>> n + 14 = 18
★ Now transposing 14 which is in L.H.S. into R.H.S. (Remember that sign would be . So 14 would be -14),
>> n = 18 - 14
>> n = 14
★ Therefore,
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