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Fantom [35]
3 years ago
9

A Local restaurant offers burgers with a choice of the following toppings: cheese, lettuce, tomato, pickle, onion, jalapeños, a

vocado, relish, ketchup, mustard and mayonnaise. How many different 3 topping burgers can be made with these toppings?
Mathematics
1 answer:
olga_2 [115]3 years ago
7 0

GD DAY AND NIGHT EMMANUEL MUDIAY

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1)The computer accessory that Joanne is considering
ankoles [38]

Answer:

Check Explanation.

Step-by-step explanation:

- A sample space includes all the possible outcomes of a statistical event. It refers to all the possible results, values that a statistical event can take on.

- Any required probability = (number of outcomes in the sample space for that event)/(number of events in the sample space)

a) Joanne is considering selling a computer accessory at her store and the accessories come in white, beige, gray or black and as an optical mouse, mechanical mouse or trackball.

This means that an accessory can be white and an optical mouse, white and a mechanical mouse or white and a trackball.

This can be done for the 3 other colours.

So, the sample space for the accessory spans:

(white, optical mouse), (white, mechanical mouse), (white, trackball), (beige, optical mouse), (beige, mechanical mouse), (beige, trackball), (gray, optical mouse), (gray, mechanical mouse), (gray, trackball), (black, optical mouse), (black, mechanical mouse), (black, trackball)

The probability that someone gets beige and a mechanical mouse

Any required probability = (number of outcomes in the sample space for that event)/(number of events in the sample space)

Number of outcomes with an accessory that is beige and a mechanical mouse = 1

Number of events in the sample space = 12

The probability that someone gets beige and a mechanical mouse = (1/12) = 0.0833

b) Jackie has three pairs of jeans: Joe Brand, Levis and Seven. She also has 4 tops: red, blue, purple and pink.

The sample space for Jackie's outfits is;

(Joe Brand, red), (Joe Brand, blue), (Joe Brand, purple), (Joe Brand, pink), (Levis, red), (Levis, blue), (Levis, purple), (Levis, pink), (Seven, red), (Seven, blue), (Seven, purple), (Seven, pink)

The chance she wears the Joe Brand or Levis and a purple top.

Number of outcomes with an outfit of Joe Brand or Levis and a purple top = 2

number of outfits on the sample space = 12

The chance she wears the Joe Brand or Levis and a purple top = (1/6) = 0.1667

c) A surfer owns 5 wetsuits: brown, black, pants, shorts and green. He also owns 3 surf boards: blue, green and red.

Sample space includes

(brown, blue), (brown, green), (brown, red), (black, blue), (black, green), (black, red), (pants, blue), (pants, green), (pants, red), (shorts, blue), (shorts, green), (shorts, red), (green, blue), (green, green), (green, red)

The chance he has a green wetsuit and surfboard

Number of outcomes in the sample space with green wetsuit and a green surfboard = 1

number of outcomes in the sample space = 15

The chance he has a green wetsuit and surfboard = (1/15) = 0.0667

Hope this Helps!!!

4 0
3 years ago
.
labwork [276]
The correct answer would be C

Hope this helped
8 0
3 years ago
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
3 years ago
How do you find the perimeter of the window to the nearest tenth. Half the widows radius is 20.
muminat

Answer:

Step-by-step explanation:

Bsbsbdvd devebehehevergrbrhrhrhjddududyZhhdbdbsgssgsggsUhfhd

7 0
3 years ago
A rectangle has a perimeter of 42 m and a width of 9 m. What is the length in meters.
Vlad [161]

Answer:

12 meters

Step-by-step explanation:

2x9=18 (get both widths)

42-18=24 (take away widths of 9m)

24/2=12 (divide by 2 to get one length)

5 0
2 years ago
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