Answer:
We conclude that the machine is under filling the bags.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 436.0 gram
Sample mean, 
= 429.0 grams
Sample size, n = 40
Alpha, α = 0.05
Population standard deviation, σ = 23.0 grams
First, we design the null and the alternate hypothesis
We use one-tailed(left) z test to perform this hypothesis.
Formula:
Putting all the values, we have
Now, 
Since,
We reject the null hypothesis and accept the alternate hypothesis. Thus, we conclude that the machine is under filling the bags.
Your answer would be 4 over x to the sixth which would look like this
4
_
x^6
the ^ symbol means it’s an exponent
Cost of 380 gram of sweets = (2.1/50) * 380 = $15.96
Answer:
Step-by-step explanation:
a.) The worst-case height of an AVL tree or red-black tree with 100,000 entries is 2 log 100, 000.
b.) A (2, 4) tree storing these same number of entries would have a worst-case height of log 100, 000.
c.) A red-black tree with 100,000 entries is 2 log 100, 000
d.) The worst-case height of T is 100,000.
e.) A binary search tree storing such a set would have a worst-case height of 100,000.
Answer:
a) 4.387
b) Yes, because np & npq are greater than 10.
c) = 0.017
Step-by-step explanation:
Give data:
p = 0.69
n = 90
a) a
E(X) = np = 62.1
= 4.387
b)
np = 62.1
q = 1 - p = 1 - 0.69 = 0.31
npq = 19.251
Yes, because np & npq are greater than 10.
c.
[continuity correction]
= P(Z> 2.14 )
= 1 - P(Z<2.14)
= 1 - 0.983 (using table)
= 0.017
