the factor by which a logarithm of a number to one base is multiplied to obtain the logarithm of the number to a new base. b : absolute value sense 2.

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4 0

2 years ago

Because of a problem in the program, the timer in a video player did not begin counting until the video had been playing for sev

777dan777 [17]

Answer:

105 frames

Step-by-step explanation:

Given that:

At 0 seconds, the video had already played 190 frames and there are 25 frames being played per second.

When the time is equal to $3 \dfrac{2}{5}$ , the number of frames that are already being played is:

$= 3 \dfrac{2}{5} \times 25$

$= \dfrac{17}{5} \times 25$

= 17 × 5

= 85 frames.

But recall that, the frames had already played 190 frames at 0 seconds, then the number of frames that had already been played when the time is equal to $3 \dfrac{2}{5}$ is;

=(190 - 85) frames

= 105 frames

7 0

3 years ago

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