We can see that, when the input is 5, the output is 24.
<h3>
How to evaluate an equation?</h3>
Here we have the equation:
Where y is the output and x is the input.
We want to evaluate it with the input as 5, so we need to replace the variable x by the number 5, we will get:
Then we can see that, when the input is 5, the output is 24.
If you want to learn more about evaluating functions:
brainly.com/question/1719822
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Hello,
A: roots: -1,-3
a point (-2,1)
Vertex=((-2,1)
y=k*(x+1)(x+3) using roots
but k*(-2+1)(-2+3)=1==>k*(-1)*1=1==>k=-1
eq: y=-(x+1)(x+3)
==>y=-(x²+3x+x+3)
==>y=-x²-4x-3
y=k(x+2)²+1 if x=-1,y=0 ==>k*1+1=0==>k=-1
==>y=-(x+2)²+1
Answer :A--> R,K
B)
y=k(x+4)²-2 and k=-1/2
y=-1/2(x+4)²-2
y=-1/2x²-4x-10
answer B--> I,≈W if it is written -1/2*x² (square has been forgotten)
C:
y=2x²-16x+30
y=2(x-4)²-2
answer : C-->S,J
D:
y=-(x+3)(x+1)
y=-x²-4x-3
=-(x+2)²+1
answer D--> V,L
E:
Here there is a problem: or the graph is wrong, or 2 equations are missing!
y=1(x+1)(x-3) using roots
y=x²-2x-3 ≈ T si it were -2x and not +2x.
y=(x-1)²-4 ≈H is it were -1 in place of +1 [H:y=(x+1)²-4]
Factoring the expression would be 6a(2a^2+4a-1)
Answer:
Step-by-step explanation:
B(0, -14) ⇒ x₁ = 0 & y₁ = -14
F(4,6) ⇒ x₂ = 4 & y₂ = 6
Answer:
C) -6-(-3)=3
Step-by-step explanation:
-6-(-3)=
-6+3=
-3 (Not positive 3)
So the third one is incorrect
