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jok3333 [9.3K]
3 years ago
3

A student solves the following equation for all possible values of x: StartFraction 8 Over x 2 EndFraction = StartFraction 2 Ove

r x minus 4 EndFraction His solution is as follows: Step 1: 8(x â€" 4) = 2(x 2) Step 2: 4(x â€" 4) = (x 2) Step 3: 4x â€" 16 = x 2 Step 4: 3x = 18 Step 5: x = 6 He determines that 6 is an extraneous solution because the difference of the numerators is 6, so the 6s cancel to 0. Which best describes the reasonableness of the student’s solution?.
Mathematics
2 answers:
noname [10]3 years ago
8 0

Answer:jj

Step-by-step explanation:

Alenkasestr [34]3 years ago
5 0

Answer:

Keep it simple. C is the answer

Step-by-step explanation:

Answer:

C) His solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.

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The metro theater has 20 rows of seats with 18 Seats in each row. The theaters income in dollars if all seats are sold is (20x18
quester [9]
It would be $1,800
You would use the distributive property to do 18x5 and then 20x5 and then add those to get 1,800
4 0
3 years ago
5squared - 2 (4-3)<br>Need to show work please!
iogann1982 [59]

5 ^{2}  = 25
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6 0
3 years ago
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Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

15x(x^2-3x+2x-6)=0

15x((x^2-3x)+(2x-6))=0

15x(x(x-3)+2(x-3))=0

15x(x-3)(x+2)=0

Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

7 0
4 years ago
23.) Clarissa earns $300 per
Talja [164]

Answer:

e = 300 + .0275c

Step-by-step explanation:

So the earnings = e

Then she earns $300 and a bonus for cosmetics : 2.75%c which is equal to 0.0275 c or .0275c the c for cosmetics.

Thus the answer becomes :

e = $300 + .0275c

HOPE THIS HELPED

3 0
3 years ago
What is the quotient when (x+3) is divided into the polynomial 2x2+3x-9
maks197457 [2]
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2x^2+(-3+6)x-9
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Factor the polynomial by factoring out the greatest common factor, 2x-3
(x+3) (2x-3). So, the quotient is 2x-3



4 0
3 years ago
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