Problem: 2x^2+3x-9 For a polynomial of the form, ax^2+bx+c rewrite the middle term as the sum of two terms whose product a·c=2·-9=-18 and whose sum is b=3. Factor 3 out of 3x 2x^2+3(x)-9 Rewrite 3 as -3 plus 6. 2x^2+(-3+6)x-9 Apply the distributive property 2x^2(-3x+6x)-9 Remove the parentheses 2x^2-3x+6x-9 Factor out the greatest common factor from each group Group the first two terms and the last two terms (2x^2-3x) (6x-9) Factor out the greatest common factor in each group. x(2x-3)+3(2x-3) Factor the polynomial by factoring out the greatest common factor, 2x-3 (x+3) (2x-3). So, the quotient is 2x-3
