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lesantik [10]
4 years ago
14

What is

a1" title=" \frac{2ax + 3}{ax + 3} = - 1" alt=" \frac{2ax + 3}{ax + 3} = - 1" align="absmiddle" class="latex-formula">
x value​
Mathematics
2 answers:
Anvisha [2.4K]4 years ago
8 0

\dfrac{2ax+3}{ax+3}=-1

Rewrite -1 as a fraction

\dfrac{2ax+3}{ax+3}=\dfrac{-1}{1}

Cross multiply

2ax+3=-1(ax+3)

Distribute the -1

2ax+3=-ax-3

Add both sides by ax

3ax+3=-3

Subtract both sides by 3

3ax=-6

Divide both sides by 3a

x=-\dfrac{6}{3a}

Simplify

=-\dfrac{2}{a}

That's the value of x respect to a. Let me know if you need any clarifications, thanks!

gayaneshka [121]4 years ago
8 0

Answer:

Step-by-step explanation:

\frac{2ax+3}{ax+3} =-1\\2ax+3=-ax-3\\2ax+ax=-3-3\\3ax=-6\\x=-\frac{2}{a}

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a)(2,-1), c)(0,1), e)(-2,1)​

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5 0
3 years ago
Worth TONS of points!!! This test is super important so do not give me guesses be at least 95% sure of your answer. Answer all p
ycow [4]
1. (f+g)(x)=7x^3-3x^3-8x^2+10x-2x-12=4x^3 - 8x^2 + 8x - 12

2. fg(x)=6-5(6x^2+x)=6-30x^2-5x

3. x^2+18x=44   | +36
    x^2+18x+36=44+36
    (x+6)^2=80

4. 2x+4y=20   |:2
    x+2y=10
    3x+2y=26
-----------------
   3x-x=26-10
   2x=16
   x=16:2
x=8

x+2y=10
8+2y=10
2y=10-8
2y=2
y=2:2
y=1

5. 14x+y= -4
     y= -4 -14x
   y=3x^2-11x-4
   -4 -14x = 3x^2-11x-4      |+4
       -14x=3x^2-11x    |+14x
       0=3x^2+3x
      3x(x+1)=0
x=0 or x=-1 is the solution

6. x^2-6x+8= x^2-2x-4x+8= x(x-2)-4(x-2)=(x-2)(x-4)

7. x^2-6x-27=0
     x 1= (-6+V36+4*27)/2= (-6+V144)/2= (-6+12)/2=6/2=3
    x2= (-6-12)/2= -18/2= -9

the point are ( 3,0) and (-9.0)
   



3 0
3 years ago
Read 2 more answers
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