Not necessarily.
and
may be linearly dependent, so that their span forms a subspace of
that does not contain every vector in
.
For example, we could have
and
. Any vector
of the form
, where
, is impossible to obtain as a linear combination of these
and
, since
unless
and
.
Answer:
9
Step-by-step explanation:
I am pretty sure that addiction because if you add 198 6 times it woyuld be the same as multiplyaction
Answer: -4
Step-by-step explanation: -4 because 28 divided by -7 = -4