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2 years ago

What is product in math.

Mathematics

1 answer:

sleet_krkn [62]2 years ago

6 0

Answer:

so when you Mutpliy #*# = #product

Step-by-step explanation:

EX: 3*4=12

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If y=2ln(x2+2)y=2ln⁡(x2+2), find the equation of the tangent line to the curve at x=4x=4.

Gwar [14]

Y=21n(x2+2)y=21n(x2+2)
21n(x2+2)(y-1)=0
n=0, x=i/2-i/2, y=1

8 0

4 years ago

-X/10 = 1/5<br> What is the answer

Georgia [21]

The answer is x=-2

Solve for X by simplifying both sides of the equation, then isolating the variable.

7 0

3 years ago

Evaluate the expression

Airida [17]

Answer:

Step-by-step explanation:

(5x -2y) / y

Let x = -4 and y = -4

(5*-4 - 2*-4) / -4

(-20 +8) / -4

-12/ -4

5 0

3 years ago

Read 2 more answers

Which two values of X are roots of the polynomial below 4x^2-6x+1

PtichkaEL [24]

$4x^2-6x+1=0\\\\a=4,\ b=-6,\ c=1\\\\\Delta=b^2-4ac\\\\\Delta=(-6)^2-4(4)(1)=36-16=20\\\\\sqrt\Delta=\sqrt{20}=\sqrt{4\cdot5}=\sqrt4\cdot\sqrt5=2\sqrt5\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a},\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\x_1=\dfrac{-(-6)-2\sqrt5}{2\cdot4}=\dfrac{3-\sqrt5}{4}\\\\x_2=\dfrac{-(-6)+2\sqrt5}{2\cdot4}=\dfrac{3+\sqrt5}{4}$

5 0

4 years ago

Two cars leave at the same time from points A and B, the distance between them is 280 km. If the cars meet each other, they’ll m

kykrilka [37]

Set up the following equations:

$2x + 2y = 280$

$14x - 14y = 280$

x represents car A's speed, and y represents car B's speed.

We'll use elimination to solve this system of equations. Multiply the first equation by 7:

$(2x + 2y = 280) * 7 = 14x + 14y = 1960$

$14x - 14y = 280$

Combine both equations:

$28x = 2240$

Divide both sides by 28 to get x by itself:

$x = 80$

The speed of car A is 80 mph.

Since we now know the value of one of the variables, we can plug it into the first equation:

$2(80) + 2y = 280$

$160 + 2y = 280$

Subtract 160 from both sides.

$2y = 120$

Divide both sides by 2 to get y by itself:

$y = 60$

The speed of car B is 60 mph.

7 0

4 years ago