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astra-53 [7]
3 years ago
14

They are 3 boys and 5 girls standing at the entrance to the school fair. Each child is holding 3 balloons. One sixth of the ball

oons are red. There are twice as many green balloons as red ones. The rest are blue.
Mathematics
1 answer:
DerKrebs [107]3 years ago
8 0
What is your question?
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The cup, on the 9th hole of a golf course, is located, dead center, in the middle of a circular green, which is 35 feet in radiu
ale4655 [162]

Answer:

± 27.33 ft

Step-by-step explanation:

For the given problem, we can estimate the initial and final coordinates of the line of the ball path as (-40,-50) and (0,0). Therefore, the slope is:

(-50-0)/(-40-0) = 50/40 = 1.25

Similarly, we can estimate the slope of a perpendicular line to the line of the ball path as: -1*(1/1.25) = -0.8.

Therefore, using (0,0) and the slope -0.8, the equation of the perpendicular line is: -0.8 = (y-0)/(x-0);

-0.8 = y/x

y = -0.8x

Furthermore, we are given the circle radius as 35 ft and we can use the distance formula to find the two points 35 ft far from the origin:

35^2 = x^2 + y^2

y = -0.8x

35^2 = x^2 + (-0.8x)^2

1225 = (x^2 + 0.64x^2)

1225 = 1.64x^2

x^2 = 1225/1.64 = 746.95

x = sqrt(746.95) = ± 27.33 ft

5 0
3 years ago
Alon was curious if segments \overline{JK} JK start overline, J, K, end overline and \overline{NM} NM start overline, N, M, end
BartSMP [9]

The answer is A because Alon could have rotated the figure and discovered that they are congruent

6 0
3 years ago
Which properties are used to prove that the expressions 5x+x-2 and 6x-2 are equivalent? 5x+x-2 (5+1)x-2 6x-2
sergeinik [125]

Answer:

Associative and Commutative properties

Step-by-step explanation:

7 0
3 years ago
For which values of k, do the pair of linear equations
Allushta [10]

Answer:

a unique solution......

6 0
3 years ago
The scores for a certain test of intelligence are normally distributed with mean 85 and standard deviation 11. Find the 90th per
jonny [76]

Answer:

99.1 is the 90th percentile of these scores.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 85

Standard Deviation, σ = 11

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.90

P( X < x) = P( z < \displaystyle\frac{x - 85}{11})=0.90  

Calculation the value from standard normal z table, we have,  

P(z \leq 1.282) = 0.90

Putting values, we get,

\displaystyle\frac{x - 85}{11} = 1.282\\\\x = 99.1

Thus, 99.1 is the 90th percentile of these scores.

5 0
3 years ago
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