Find all real values of $x$ such that $x^2-5x + 4=0$.
2 answers:
Answer:
Find the 58th term of the arithmetic sequence
−20
Step-by-step explanation:
Answer:
x=4 && x=1
Step-by-step explanation:
x^2 - x - 4x + 4=0
x(x-1) - 4(x - 1)=0
(x-4)(x-1)=0
X=4 and x=1
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