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andrey2020 [161]
3 years ago
7

Find the result when 40 is increased by 85%

Mathematics
1 answer:
miskamm [114]3 years ago
3 0
47.05 is the anwser. When I used the calculator.
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Ap calc multiple choice question; attached below<br> please explain how, please!
anygoal [31]

Answer:

C. \frac{f(b)-f(1)}{b-1}=20

General Formulas and Concepts:

<u>Calculus</u>

  • Mean Value Theorem (MVT) - If f is continuous on interval [a, b], then there is a c∈[a, b] such that  f'(c)=\frac{f(b)-f(a)}{b-a}
  • MVT is also Average Value

Step-by-step explanation:

<u>Step 1: Define</u>

f(x)=e^{2x}

f'(c) = 20

Interval [1, b]

<u>Step 2: Check/Identify</u>

Function [1, b] is continuous.

Derivative [1, b] is continuous.

∴ There exists a c∈[1, b] such that f'(c)=\frac{f(b)-f(a)}{b-a}

<u>Step 3: Mean Value Theorem</u>

  1. Substitute:                    20=\frac{ f(b)-f(1)}{b-1}
  2. Rewrite:                        \frac{ f(b)-f(1)}{b-1}=20

And we have our final answer!

5 0
3 years ago
The number 6 is halfway between 4.5 and 7.5.
Natasha2012 [34]
6=\frac{2.8+x}{2}\\&#10;12=2.8+x\\&#10;x=9.2\\&#10;\\&#10;\\&#10;6=\frac{-12+x}{2}\\&#10;12=-12+x\\&#10;x=24
4 0
3 years ago
Show work for this scientific notation
Viktor [21]

\frac{5.1*10^{-2}}{4.57*10^{-4}} \\=\frac{5.1*10^{2}}{4.57} \\=\frac{5.1}{4.57}*10^{2}\\=1.1*10^{2}

The answer is rounded to the nearest tenth.

7 0
3 years ago
Under certain conditions, the number of bacteria present in a colony is approximated by f(t) = Age 0.023t, where t is in minutes
AleksandrR [38]

Answer:

  • 5 min: 3,029,058
  • 10 min: 3,398,220
  • 60 min: 10,732,234

Step-by-step explanation:

The given function is evaluated by substituting the given values of t. This requires using the exponential function of your calculator with a base of 'e'. Many calculators have that value built in, or have an e^x function (often associated with the Ln function).

__

<h3>5 minutes</h3>

The number of bacteria present after 5 minutes is about ...

  f(5) = 2.7×10^6×e^(0.023×5) ≈ 3,029,058

<h3>10 minutes</h3>

The number of bacteria present after 10 minutes is about ...

  f(10) = 2.7×10^6×e^(0.023×10) ≈ 3,398,220

<h3>60 minutes</h3>

The number of bacteria present after 60 minutes is about ...

  f(60) = 2.7×10^6×e^(0.023×60) ≈ 10,732,234

8 0
2 years ago
Seriously need help!!????
Serga [27]
50 would be a good choice of answer
3 0
3 years ago
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