The value x = - 2 is not part of the domain of the function f(x) = √(x + 1).
<h3>Is a given point part of the domain of a radical function?</h3>
Radical functions are functions that involves root operators. We see here a radical function of the form f(x) = √(x + a), whose domain is x ∈ [- a, + ∞), that is, x ≥ - a. If we know that f(x) = √(x + 1), then a = 1 and the domain of the function is x ∈ [- 1, + ∞), that is, x ≥ - 1.
Hence, the value x = - 2 is not part of the domain of the function f(x) = √(x + 1).
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Answer:
96 for both
Step-by-step explanation:
You can see that each region is equal because it is half. 8*12=96. (96/2)*2= Shaded region. 96
So that means the unshaded region is also 96.
Answer:
8 represents the temperature at the mid night of Friday was 8°.
Step-by-step explanation:
The weather service measures the temperature, T, every hour, h, beginning at midnight of each 24-hour period.
If on Friday, the temperature was modeled by T = 43h + 8.
That means at h =0 i.e. at the midnight the temperature T is given by 8.
So, 8 represents the temperature at the midnight of Friday was 8°. (Answer)
Answer:
<em>On day the he covers </em>128.4 ft²
<u>Step-by-step explanation</u>:
Lets first figure out how much he has done so far
To figure out how much he does we can use a proportion
Set up a proportion for first day
2/7 = x/299.6
Solve the proportion
2×299.6÷7 = 599.2/7 = x
x = 85.6
<em>He covered 85.6 sq/ft on day 1</em>
Find day two
85.6 * 2 = 171.2
Find how much is left to do on day 3
299.6-171.2 = 128.4 ft²