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ANEK [815]
2 years ago
15

Helpppppppppppppppppp​

Mathematics
1 answer:
Lapatulllka [165]2 years ago
3 0

Answer:

62°

Step-by-step explanation:

it basically falls under the formula of SOH CAH TOA

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Plz help me ASAP it’s important
Hunter-Best [27]

Answer:

D. 6.3

Step-by-step explanation:

Well you can make a triangle with the line PQ with it's height as 2 and base as 6.

Then you can use the Pythagorean Theorem to find the length of PQ.

a²+b²=c²

2²+6²=c²

4+36=c²

40=c²

c²=40

<em>Square root both sides</em>

c=\sqrt{40}

c≈6.3

Our answer is D. 6.3

5 0
4 years ago
A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday's mail. In actuali
Dominik [7]

Answer:

y                 0             1              2          3

P(Y=y)   0.0676   0.3549   0.3875   0.19

Step-by-step explanation:

P(Wed) = 0.26

P(Thurs) = 0.39

P(Fri) = 0.25

P(Sat) = 0.10

Y = No. of days beyond Wednesday it takes for both magazines to arrive i.e. 0,1,2,3

Y=0 means the magazines will arrive on Wednesday

Y=1 means the magazines will arrive till Thursday

Y=2 means the magazines will arrive till Friday

Y=3 means the magazines will arrive till Saturday

The possible combinations for Y are

Y(W,W) Y(W,T) Y(W,F) Y(W,S)

Y(T,W) Y(T,T) Y(T,F) Y(T,S)

Y(F,W) Y(F,T) Y(F,F) Y(F,S)

Y(S,W) Y(S,T) Y(S,F) Y(S,S)

So, we can classify these possible outcomes as Y=0,1,2,3.

Y(0) = Y(W,W) (both magazines take 0 days to arrive beyond Wednesday)

Y(1) = Y(W,T), Y(T,T), Y(T,W) (both magazines take 1 day to arrive beyond Wednesday)

Y(2) = Y(W,F), Y(T,F), Y(F,F) Y(F,W) Y(F,T) (both magazines arrive till Friday)

Y(3) = Y(W,S), Y(T,S), Y(F,S), Y(S,W), Y(S,T), Y(S,F), Y(S,S) (both magazines arrive till Saturday)

To calculate the PMF, we need to calculate the probability for each of the points in Y(0,1,2,3).

Y(0) = Y(W,W)

       = 0.26 x 0.26

Y(0) = 0.0676

Y(1) = Y(W,T) + Y(T,T) + Y(T,W)

      = (0.26 x 0.39) + (0.39 x 0.39) + (0.39 x 0.26)

      = 0.1014 + 0.1521 + 0.1014

Y(1) = 0.3549

Y(2) = Y(W,F) + Y(T,F) + Y(F,F) + Y(F,W) + Y(F,T)

  =(0.26 x 0.25) + (0.39 x 0.25) + (0.25 x 0.25) + (0.25 x 0.26) + (0.25 x 0.39)

  = 0.065 + 0.0975 + 0.0625 + 0.065 + 0.0975

Y(2) = 0.3875

Y(3) = Y(W,S) + Y(T,S) + Y(F,S) + Y(S,W) + Y(S,T) + Y(S,F) + Y(S,S)

      = (0.26 x 0.10) + (0.39 x 0.10) + (0.25 x 0.10) + (0.10 x 0.26) + (0.10 x 0.39) + (0.10 x 0.25) + (0.10 x 0.10)

       = 0.026 + 0.039 + 0.025 + 0.026 + 0.039 + 0.025 + 0.010

Y(3) = 0.19

y                 0             1              2          3

P(Y=y)   0.0676   0.3549   0.3875   0.19

The PMF plot is attached as a photo here.

7 0
4 years ago
Proving the converse of the parallelogram side theorem
Alenkinab [10]

Answer:

What exactly are you asking?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Simplify seven square root of three end root minus four square root of six end root plus square root of forty eight end root min
Cloud [144]

7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54} simplified as 11\sqrt{3}- 7\sqrt{6} or 1.909 .

<u>Step-by-step explanation:</u>

We need to Simplify seven square root of three end root minus four square root of six end root plus square root of forty eight end root minus square root of fifty four. Which is equivalent to 7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54} :

7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54}

⇒ 7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{44}

⇒ 7\sqrt{3}- 4\sqrt{6} + \sqrt{16(3)} - \sqrt{9(6)}

⇒ 7\sqrt{3}- 4\sqrt{6} + 4\sqrt{(3)} - 3\sqrt{(6)}

⇒ 11\sqrt{3}- 4\sqrt{6}- 3\sqrt{(6)}

⇒ 11\sqrt{3}- 7\sqrt{6}

\sqrt{3} = 1.732 , \sqrt{6} = 2.449

⇒ 11(1.723)- 7(2.449)

⇒ 1.909

Therefore, 7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54} simplified as 11\sqrt{3}- 7\sqrt{6} or 1.909 .

6 0
3 years ago
Find m &lt; E (Image Below)
lyudmila [28]

Answer:

uiuiuiui86767

Step-by-step explanation:

your answer is e330408384

4 0
3 years ago
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