2 years ago

Answer for brainliest

Mathematics

1 answer:

Tcecarenko [31]2 years ago

5 0

Answer:
If this is what your looking for, the answer may be:
-4y + 12
Hope this helps!

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A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time

user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

$a(t) = 24t + 2$

Velocity:

$v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K$

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

$v(t) = 12t^{2} + 2t + 13$

Position:

$s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K$

Since s(0) = 3

$s(t) = 4t^{3} + t^{2} + 13t + 3$

What is its position at time t=5?

This is s(5).

$s(t) = 4t^{3} + t^{2} + 13t + 3$

$s(5) = 4*5^{3} + 5^{2} + 13*5 + 3$

$s(5) = 593$

It's position at time t = 5 is 593.

3 0

3 years ago

Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following p

strojnjashka [21]

Answer:

P(X = 3) = 0.14680064

Step-by-step explanation:

Formula=============================

$p\left( X=k\right) =C^{k}_{n}p^{k}(1-p)^{n-k}\ \ ;\ k\in \left\{ 0,\ldots ,n\right\}$

……………………………………………………………………..

Given :

n = 8

p = 0.2

1 - p = 1 - 0.2 = 0.8

k = 3

Then

$p\left( X=3\right) =C^{3}_{8}(0.2)^{3}(0.8)^{5}$

$=0.14680064$

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1 year ago

Which graph represents the solution set to the system of inequalities? Please help thank you!

Greeley [361]

Answer:

bottom left graph should be correct

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James made a deposit in a savings account 5 years ago. The account pays 4% simple annual interest. Since then, he has earned $12

Lera25 [3.4K]

P=i/rt
P=120/0.04*5=600

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3 years ago

34 pages in 10 mins in unit rate

saul85 [17]

Answer:

3.4 pages per minute

Step-by-step explanation:

Divide your number of pages by the minutes to calculate the unit rate.

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