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3 years ago

13

Kaitlin wants to pour 27.17 grams of salt into a container. So far, she has poured 25.98 grams. How much more salt should Kaitli

n pour?

1 answer:

LekaFEV [45]3 years ago

5 0

Answer:

1.19

Step-by-step explanation:

27.17-25.98= 1.19

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Sever21 [200]

Rewrite 7/8 as a decimal by dividing 7 by 8:

7/8 = 0.875

Now to find how much further she has to run subtract where is now from the total distance:

0.875 - 0.3 = 0.575

She needs to run 0.575 miles more

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An airplane moves at a constant speed of 120 miles per hour for 3 hours. How far does it

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3 years ago

Anna has a total of 36 goldfish in her aquarium, some are orange and some are black. The number of orange goldfish is 7 more tha

andriy [413]

Answer:

x + y = 36.....Equation 1

x = 7 + 2y...... Equation 2

Step-by-step explanation:

Let the number of:

Orange goldfish = x

Black gold fish = y

Anna has a total of 36 goldfish in her aquarium, some are orange and some are black.

x + y = 36.....Equation 1

The number of orange goldfish is 7 more than twice the number of black goldfish.

x = 7 + 2y...... Equation 2

We can rewrite this as:

x - 2y = 7..... Equation 2

The system of equations below that can be used to describe the number of black and orange goldfish in Anna's aquarium is :

x + y = 36.....Equation 1

x = 7 + 2y...... Equation 2

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2 years ago

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clark made four of his truck payments late and was fined four late fees the total change to his savings from late fees was -$44

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11 dollars is one late fee because 44 divided by 4 is 11. I hope this helps cx

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3 years ago

Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''

Nonamiya [84]

Answer:

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

$D^2-1=0$

$(D-1)(D+1)=0$

D=1,-1

Then , the solution of given differential equation

$y=e^x,y=e^{-x}$

2. $7x^2y''+14xy'-14 y=0$

Y= $y=x^3$

$y=3x^2$

$y''=6x$

Substitute in the given differential equation

$42x^3+42x^3-14x^3\neq 0$

Hence, $x^3$ is not a solution of given differential equation

$e^x,e^{-x}$ are also not a solution of given differential equation.

y= $x^{-2}$

$y'=-2x^{-3}$

$y''=6x^{-4}$

Substitute the values in the differential equation

$7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}$

= $42x^{-2}-28x^{-2}-14x^{-2}=0$

Hence, $x^{-2}$ is a solution of given differential equation.

c. $7x^2y''-42y=0$

$y=x^3$

$y'=3x^2$

$y''=6x$

Substitute the values in the differential equation

$42x^3-42x^3=0$

Hence, $x^3$ is a solution of given differential equation.

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

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3 years ago

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