Answer:
Step-by-step explanation:
-7/5=-1.400
-1 5/11=-16/11=-1.455...
-1.450
-1 91/200=-291/200=-1.405
-1.455 <-1.450 <-1.405 <-1.400
- 1 5/11 <-1.45 <- 91/200 <-7/5
The diagram is attached below
Beaker 1: The measurement line is between 32 and 33. There are 5 lines between 32 and 33. Making line is between third line and fourth line(between 6 and 8). So 32.7
Beaker 2: The measurement line is between 30 and 40. We can clearly see the measurement line at 32. So its 32
Beaker 3: The measurement line is between 32.7 and 32.8. We have 10 small lines inbetween them. Measurement line at 4. So its 32.74
(b) the amount of water in each of 3 beakers are not same because we can measure the difference. But they are close to each other.
Answer:
2nd option is the answer
Step-by-step explanation:
I can help if you want me to
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Equation of regression line :
Yˆ = −114.05+2.17X
X = Temperature in degrees Fahrenheit (°F)
Y = Number of bags of ice sold
On one of the observed days, the temperature was 82 °F and 66 bags of ice were sold.
X = 82°F ; Y = 66 bags of ice sold
1. Determine the number of bags of ice predicted to be sold by the LSR line, Yˆ, when the temperature is 82 °F.
X = 82°F
Yˆ = −114.05+2.17(82)
Y = - 114.05 + 177.94
Y = 63.89
Y = 64 bags
2. Compute the residual at this temperature.
Residual = Actual value - predicted value
Residual = 66 - 64 = 2 bags of ice