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andrew11 [14]
3 years ago
14

Point Bis the midpoint of AC AB=2x and AC=3x+20. What is the value of x?

Mathematics
1 answer:
horsena [70]3 years ago
7 0

Answer:

So x = 20

Step-by-step explanation:

AB + BC = AC sum of a segment is sum of its pieces

AB + AB = AC B is the midpoint, so AB = BC

2x + 2x = 3x + 20 putting in for AB (twice!) and AC

4x = 3x + 20 collect like terms

x = 20 subtract 3x on both sides.

Read more on Brainly.com - brainly.com/question/10838483#readmore

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Sekhar gives a quarter of his sweets to Renu and then gives 5 sweets to Raji. He has
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I think your question seems to be :-

Write the equation of the circle that has a center of (-7, 17) with a radius of √19

So , as we know that the equation of circle with centre at <em>(h,k)</em> and <em>radius r</em> is given by {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}} . Now , using same concept in this question ;

{:\implies \quad \sf \{x-(-7)\}^{2}+(y-17)^{2}=(\sqrt{19})^{2}}

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