What value should go in the empty box to complete the calculation for finding the product of 73.458 × 0.39?

Alberta Doan worked 6 hours at time-and-a-half pay and 3 ¼ hours at double-time pay. Her regular pay rate was $9.72 an hour. Wha

natka813 [3]

Answer:

Alberta's total overtime pay of the week was $ 145.80.

Step-by-step explanation:

Given that Alberta worked 6 hours at time-and-a-half pay, and 3 hours at double-time pay, and that the value of her regular work hour is $ 9.72, to determine the value of the pay of his overtime, the following equation must be performed:

6x1.5x9.72 + 3x2x9.72 = X

9x9.72 + 6x9.72 = X

87.48 + 58.32 = X

145.8 = X

Therefore, Alberta's total overtime pay of the week was $ 145.80.

3 0

3 years ago

Solve the equation. Check your solution.

zzz [600]

I’m pretty sure it’s -4

3 0

3 years ago

Can someone please help me with 4 and 5 ???

Montano1993 [528]

Answer:

4. D

A: -25.5=a

B: b=-4

C: c=12

D: d=8

Step-by-step explanation:

4.Between a and d they are the 2 bigger values but D was the greatest out of all of them. - divided by a - will result as a positive and 7/9=0.77 and 19/12 *I looked for the least common factor and multiplied numerator and denominator to 12 depending on the denominators value. Ex: since one of my denominators was 4, I multiply the whole fraction by 3 to get 9/12 and the other was 5/6 times 2 is 10/12 and just add 10/12 by 9/12 which is 19/12.

5.

A: All I did was multiply 8.5 and -3 and get -25.5=a.

B: I add 7 on both sides of the equation and -7 and 7 get canceled off and -11+7=-4. b=4.

C: I multiplied - to -3 and got 3, now I can subtract -3 on both sides. 15-3=12 so c=12.

D. I had to divide by 4 on both sides to get d by itself. 32/4=8 so final answer would be d=8.

5 0

3 years ago

How to solve using Substitution or Elimination? y=3x-1 y=2x+2

n200080 [17]

By elimination:

y = 3x - 1

y = 2x + 2

Subtract the second equation from the first

0 = x - 1

y = 2x + 2

Subtract the first equation from the second

0 = x - 1

y = x + 3

Subtract the first equation from the second again

0 = x - 1

y = 4

Subtract x from both sides of the first equation

- x = - 1

y = 4

Divide the first equation by (-1)

x = 1

y = 4

<h3>So, the solution is x = 1 and y = 4 {or: (1, 4)}</h3>

4 0

3 years ago

Which is not an equation of the line going through (3, -6) and (1, 2)?

777dan777 [17]

Answer:

B, C

Step-by-step explanation:

The equation of a line can be given by y -y₁= m(x -x₁), where m is the slope. This is also known as the point-slope form.

$\boxed{ slope = \frac{y _{1} - y_2 }{x_1 - x_2} }$

Slope of the line

$= \frac{2 - ( - 6)}{1 - 3}$

$= \frac{2 + 6}{ - 2}$

$= \frac{8}{ - 2}$

= -4

Substitute m= -4 into the equation:

y -y₁= -4(x -x₁)

Substitute a pair of coordinates into (x₁, y₁):

Let's start by substituting (1, 2).

y -2= -4(x -1)

This gives us the same equation as D, making D an incorrect option. Note that the question asks for which is not the correct equation.

Let's change the above into the slope-intercept form, where by y is the subject of formula.

Start by expanding the right-hand side:

y -2= -4x +1

+2 on both sides:

y= -4x +3

This equation is not the same as C. C is thus the correct option.

Let's check for options A and B.

The equation in option B is not the correct equation either as they have substituted (2, 1) instead of (1, 2) into (x₁, y₁). Thus, option B is also correct.

y -y₁= -4(x -x₁)

Substitute (3, -6) into (x₁, y₁):

y -(-6)= -4(x -3)

y +6= -4(x -3)

This is the same as option A, making option A incorrect too.

4 0

2 years ago