Let the investment in first account be x and this account is earning 3% interest
So Interest on this account is 3% of x = 0.03x
So the investment in second account would be (7000-x) and this account is earning 7% interest
So the interest on this account is 7% of (7000-x) = 0.07*(7000-x)
Given that total interest for the year is $262
So we have
0.03x + 0.07(7000-x) = 262
0.03x - 0.07x + 0.07*7000 = 262
-0,04x + 490 = 262
-0.04x = 262-490
-0.04x = - 228
0.04x = 228x
x = 228/0.04
x = 5700
Therefore Investment in one account s 5700 and the investment in other account is 7000-5700 = 1300
Answer:
the interquartile range is 7
Answer:
C
Step-by-step explanation:
A reflection of a graph on the x axis simply adds the opposite sign to the x^2, in this case, since f(x) = x^2 is positive, a reflection would mean that g(x) would be -x^2. As g(x) is also vertically translated down 2 units, the equation would then become g(x) = -x^2 - 2 and the correct answer would be C.
1.9+n
2.10+6
3.2+10
4.17
5.3+3
6.-3+n
Circumference's formula is: 2πr
Since π is not added in the total (as it is 28π), just divide 28 with 2 to get r
28/2 = 14
The radius is 14
hope this helps
