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Afina-wow [57]
2 years ago
5

Pls help with stats

Mathematics
1 answer:
aleksklad [387]2 years ago
3 0

Answers:

  1. Exactly 25%
  2. median = 450
  3. Not enough info (see below)
  4. IQR = 24
  5. IQR = 192

=========================================================

Explanations:

  1. By definition, the quartiles split the data into four equal parts. The first quartile (Q1) will have 25% of the data below it.
  2. The second quartile is the exact same value as the median. This is because the median splits the data into two equal halves, i.e. is at the midpoint.
  3. There's not enough info. We can determine that 25% of the company makes more than $60,000, but we don't know how many people total work at the company. This info is missing.
  4. Subtract the third and first quartiles (Q3 and Q1) to get the interquartile range (IQR). So IQR = Q3 - Q1 = 45-21 = 24
  5. Same idea as the previous problem. IQR = Q3 - Q1 = 316.5 - 124.5 = 192
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defon

Answer:

1. x =0; x = -7

2. x = -3; x = 10

3. x = -5; x = -4

Step-by-step explanation:

(1). 6x² + 42x = 0

6x (x + 7) = 0

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x = 0/6. x = 0 - 7

x = 0. x = -7

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x = -7

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x² + 4x + 5x + 20 = 0

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6 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!
aleksley [76]

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Explanation:

It is given that the length of the hypotenuse is 10 units.

Also, the angle of R is 64°

To find the length of PR, we shall use the cosine formula,

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Substituting these values in the formula, we get,

\cos 64=\frac{P R}{10}

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Multiplying, we have,

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Rounding off, we get,

PR=4.4

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8 0
3 years ago
The question is :
vovikov84 [41]
You are correct, the profit is modeled by:
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We are also told that "t" is the number of years after 2010. So in 2016, the value of t will be 6. We substitute this into the equation we formed:

-0.1(6²) + 6(6) + 67
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3 0
3 years ago
Which two numbers go into the blanks so they add to be the bottom number but also multiply to be the top?
ss7ja [257]

Answer:

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Step-by-step explanation:

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3 years ago
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jarptica [38.1K]

Answer:

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<h3>Hope it is helpful....</h3>
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