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7nadin3 [17]
3 years ago
9

Ken paid 412 for two magazines. The cost of each magazine was multiple of 43. What are the possible prices of the magazines

Mathematics
2 answers:
maria [59]3 years ago
8 0
25, 43, 68, 111, 154, 197, 240, 283, 326, 369.

412 - 43 = 369
412 - 86 = 326
and so on.
andrew11 [14]3 years ago
5 0
I'm guessing you mean magazines as in bullets. Well, if he paid $412 dollars for two, and each were sold as a multiple of 43. Then each bullet was $4.79.

You find this by dividing 412 by 2 which gives you $206.

Now divide that by 43. Which is $4.79 (.ea) bullet.
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Answer

The steel ball will be caught up in between the mercury and water medium.

Step-by-step explanation:

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From the factual density of both substances given above ,it shows that mercury is more heavier than water. In that case mercury will be at the lower layer when mixed with water.

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8 0
3 years ago
Can someone please help me Please I'm desperate
Yuri [45]

Answer:

James is 37, Rob is 44, and Kate is 35

Step-by-step explanation:

Set up an equation where x is James' age:

Rob's age can be represented by x + 7, since he is 7 years older than James

Kate's age can be represented by x - 2, since she is 2 years younger than James

Add these together in the equation and set it equal to 116:

(x + 7) + (x - 2) + (x) = 116

Add like terms and solve for x:

(x + 7) + (x - 2) + (x) = 116

3x + 5 = 116

3x = 111

x = 37

So, James is 37.

Find Rob's age by adding 7 to this:

37 + 7

= 44

Find Kate's age by subtracting 2:

37 - 2

= 35

So, James is 37, Rob is 44, and Kate is 35

4 0
2 years ago
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Try this option:
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laiz [17]
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Price after marked down = $90 - $31.50 = $58.50

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3 years ago
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