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2 years ago

Ken paid 412 for two magazines. The cost of each magazine was multiple of 43. What are the possible prices of the magazines

Mathematics

2 answers:

maria [59]2 years ago

8 0

25, 43, 68, 111, 154, 197, 240, 283, 326, 369.

412 - 43 = 369
412 - 86 = 326
and so on.

andrew11 [14]2 years ago

5 0

I'm guessing you mean magazines as in bullets. Well, if he paid $412 dollars for two, and each were sold as a multiple of 43. Then each bullet was $4.79.

You find this by dividing 412 by 2 which gives you $206.

Now divide that by 43. Which is $4.79 (.ea) bullet.

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If a stadium has 50,000 seats, how many concert tickets would have to be sold for the event to be 85% sold out?

Anvisha [2.4K]

Answer:

42500

Step-by-step explanation:

50000x0.85=42500

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2 years ago

Aisha and jordan start by making a floor plan for their treehouWhich revision of these two sentences best shows that the coach b

irina1246 [14]

Answer: Statements 1 and 2 shows that the coach blowing the whistle happened first.

Step-by-step explanation: The coach blowing the whistle as the first event can be seen only from statements 1 and 2 only.

From statement 1, "the referee blew the whistle" was followed by "the team ran onto the field."

From statement 2, "before the team ran onto the field" shows clearly that one event took place "BEFORE" the one being reported and the one that occurred before this one was "the referee blew the whistle."

Statement 3 which is "the referee blew the whistle, BUT..." indicates that the whistle was meant to prevent the team from from running onto the field. So if the referee blew the whistle, but the team ran onto the field, it means the whistle blowing was not supposed to make them run onto the field.

Statement 4, which states that "the referee blew the whistle BECAUSE the team ran onto the field" indicates that, the reason for blowing the whistle was because the team ran onto the field which clearly shows that the team ran onto the field first before the referee blew the whistle.

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8 0

2 years ago

If a pine tree grows 4 inches per year, how long will it take for the tree to reach a height of 13 feet?

attashe74 [19]

Answer:

Should be 39 years.

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5 0

3 years ago

Read 2 more answers

What property is occurring in the following example? 11.5 + (- 11.5) = 0

kramer

Answer: A property occurring in the example 11.5 + (-11.5) = 0, is additive inverse.

Step-by-step explanation:

A property where sum of any number and its inverse is equal to zero is called additive inverse property.

For example, 11.5 + (-11.5) = 0

Here, 11.5 is the number and its inverse is (-11.5). The sum of both these is equal to zero. Hence, it shows a property of additive inverse.

Thus, we can conclude that property occurring in the example 11.5 + (-11.5) = 0, is additive inverse.

5 0

2 years ago

How do you solve his with working

AlexFokin [52]

Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

$\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888$

b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.

$\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884$

7 0

3 years ago