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7nadin3 [17]
3 years ago
9

Ken paid 412 for two magazines. The cost of each magazine was multiple of 43. What are the possible prices of the magazines

Mathematics
2 answers:
maria [59]3 years ago
8 0
25, 43, 68, 111, 154, 197, 240, 283, 326, 369.

412 - 43 = 369
412 - 86 = 326
and so on.
andrew11 [14]3 years ago
5 0
I'm guessing you mean magazines as in bullets. Well, if he paid $412 dollars for two, and each were sold as a multiple of 43. Then each bullet was $4.79.

You find this by dividing 412 by 2 which gives you $206.

Now divide that by 43. Which is $4.79 (.ea) bullet.
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