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7nadin3 [17]
3 years ago
9

Ken paid 412 for two magazines. The cost of each magazine was multiple of 43. What are the possible prices of the magazines

Mathematics
2 answers:
maria [59]3 years ago
8 0
25, 43, 68, 111, 154, 197, 240, 283, 326, 369.

412 - 43 = 369
412 - 86 = 326
and so on.
andrew11 [14]3 years ago
5 0
I'm guessing you mean magazines as in bullets. Well, if he paid $412 dollars for two, and each were sold as a multiple of 43. Then each bullet was $4.79.

You find this by dividing 412 by 2 which gives you $206.

Now divide that by 43. Which is $4.79 (.ea) bullet.
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Answer:

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erastovalidia [21]

Answer:

Step-by-step explanation:

The first part of A is easy. Look at the quadratic function, and the constant, the very last number with no t stuck to it represents the height from which the object in question was originally launched. Our constant is 40, so the height of the roof from which the baseball was thrown is 40 feet. Part 2 of A is not quite as simple because it requires factoring using the quadratic formula.Before we do that, let's make our numbers a bit more manageable, shall we? Let's factor out a -8 to get

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-8(t^2-6t)=-40 Next is the take half the linear term, square it, and then add it to both sides. Our linear term is a -6. Half of -6 is -3, and -3 squared is 9, so we add 9 into the parenthesis first:

-8(t^2-6t+9)=-40+??

Because this is an equation, we can't add 9 to one side without adding the equivalent to the other side. But, we cannot forget about that -8 sitting out front there, refusing to be ignored. We didn't just add in a 9, we actually added in a -8 times 9 which is -72. That's what goes on the right side in place of the ??.

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