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7nadin3 [17]
3 years ago
9

Ken paid 412 for two magazines. The cost of each magazine was multiple of 43. What are the possible prices of the magazines

Mathematics
2 answers:
maria [59]3 years ago
8 0
25, 43, 68, 111, 154, 197, 240, 283, 326, 369.

412 - 43 = 369
412 - 86 = 326
and so on.
andrew11 [14]3 years ago
5 0
I'm guessing you mean magazines as in bullets. Well, if he paid $412 dollars for two, and each were sold as a multiple of 43. Then each bullet was $4.79.

You find this by dividing 412 by 2 which gives you $206.

Now divide that by 43. Which is $4.79 (.ea) bullet.
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There are 2504 computer science students at a school. Of these, 1876 have taken a course in Java, 999 have taken a course in Lin
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Answer:

492

Step-by-step explanation:

As per the given data of the question:

Total number of students = 2504

Number of students in Java (J) = 1876

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Number of students in C = 345

J∩L = 876

L∩C = 231

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L∩J∩C = 189

Now according to Venn-diagram as drawn below:

Number of students haven taken courses in Java and Linux both only

= J∩L - L∩J∩C

= 876 - 189

= 687

Number of students haven taken courses in Java and C both only

= C∩J - L∩J∩C

= 290 - 189

= 101

Number of students haven taken courses in C and Linux both only

= L∩C - L∩J∩C

= 231 - 189

= 42

Therefore,

Number of students only in Java = 1876 - 687 - 189 - 101 = 899

Number of students only in Linux = 999 - 687 - 189 - 42 = 81

Number of students only in C = 345 - 42 - 189 - 101 = 13

So,

Number of students who have not taken a course in any of these three subjects

= 2504 - 899 - 81 - 13 - 687 - 189 -101 - 42

= 492

Hence, the students who have not taken a course in any of these three subjects = 492.

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