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Ronch [10]
3 years ago
11

This is the question I need help with

Physics
1 answer:
Liono4ka [1.6K]3 years ago
7 0

Answer:

Explanation:

If we ASSUME that a CCW torque is positive

τ = 10sin135[8.0] - 16sin90[4.0] + 19sin160[3.0] = 12 N•m

as the result is positive, the net torque is CCW.

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What is Archimedes principle?​
trasher [3.6K]

Archimedes' principle states that a body immersed in a fluid is subjected to an upwards force equal to the weight of the displaced fluid. This is a first condition of equilibrium. We consider that the above force, called force of buoyancy, is located in the centre of the submerged hull that we call centre of buoyancy.

6 0
3 years ago
The Great Sandini is a 60 kg circus performer who is shot from a cannon (actually a spring gun). You don't find many men of his
Alex17521 [72]

Answer:

22m/s

Explanation:

Mass, m=60 kg

Force constant, k=1300N/m

Restoring force, Fx=6500 N

Average friction force, f=50 N

Length of barrel, l=5m

y=2.5 m

Initial velocity, u=0

F_x=kx

Substitute the values

6500=1300x

x=\frac{6500}{1300}=5m

Work done due to friction force

W_f=fscos\theta

We have \theta=180^{\circ}

Substitute the values

W_f=50\times 5cos180^{\circ}

W_f=-250J

Initial kinetic energy, Ki=0

Initial gravitational energy, U_{grav,1}=0\

Initial elastic potential energy

U_{el,1}=\frac{1}{2}kx^2=\frac{1}{2}(1300)(5^2)

U_{el,1}=16250J

Final elastic energy,U_{el,2}=0

Final kinetic energy, K_f=\frac{1}{2}(60)v^2=30v^2

Final gravitational energy, U_{grav,2}=mgh=60\times 9.8\times 2.5

Final gravitational energy, U_{grav,2}=1470J

Using work-energy theorem

K_i+U_{grav,1}+U_{el,1}+W_f=K_f+U_{grav,2}+U_{el,2}

Substitute the values

0+0+16250-250=30v^2+1470+0

16000-1470=30v^2

14530=30v^2

v^2=\frac{14530}{30}

v=\sqrt{\frac{14530}{30}}

v=22m/s

5 0
3 years ago
In electroplating, the object to be plated is which part of an electrolytic cell? cathode or anode
Bingel [31]

Since the anode dissolves and goes to the cathode. The object to be electroplated is kept at the cathode.

Please mark me as brainliest.

7 0
3 years ago
Read 2 more answers
A white pool ball of mass 1.0 kg moving at 10 m/s collides with
solniwko [45]

The velocity of the red ball after the collision is 5.8 m/s

Explanation:

In absence of external forces on the system, we can apply the principle of conservation of momentum. The total momentum of the system must be conserved before and after the collision, so we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 1.0 kg is the mass of the pool ball

u_1 = 10 m/s is the initial velocity of the pool ball

v_1 = 3.0 m/s is the final velocity of the pool ball

m_2 = 1.2 kg is the mass of the red ball

u_2 = 0 is the initial velocity of the red ball

v_2 is the final velocity of the red ball

Solving the equation for v2, we find the final velocity of the red ball after the collision:

v_2 = \frac{m_1 u_1-m_1v_1}{m_2}=\frac{(1.0)(10)-(1.0)(3.0)}{1.2}=5.8 m/s

Learn more about collisions:

brainly.com/question/13966693#

brainly.com/question/6439920

#LearnwithBrainly

7 0
3 years ago
A car approaches you at a constant speed, sounding its horn, and you hear a frequency of 76 Hz. After the car goes by, you hear
Talja [164]

Answer:

70.07 Hz

Explanation:

Since the sound is moving away from the observer then

f_o = f_s\frac {(v+vs)}{v} and f_o = f_s\frac {(v-vs)}{v} when moving towards observer

With f_o of 76 then taking speed in air as 343 m/s we have

76 = f_s\times\frac {(343-vs)}{343}

f_s=\frac {343\times 76}{343-v_s}

Similarly, with f_o of 65 we have

65 = f_s\times\frac {(343+vs)}{343}\\f_s=\frac {343\times 65}{343+v_s}

Now

f_s=\frac {343\times 65}{343+v_s}=\frac {343\times 76}{343-v_s}

v_s=27.76 m/s

Substituting the above into  any of the first two equations then we obtain

f_s=70.07 Hz

4 0
3 years ago
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