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lawyer [7]
3 years ago
6

What is the number at the end of an isotope’s name?

Physics
1 answer:
Lera25 [3.4K]3 years ago
6 0

Explanation:

The liquid contains only one element. -The liquid is a pure substance. The number at the end of an isotope's name is the -mass number. While looking at xenon (Xe) on the periodic table, a student needs to find an element with a smaller atomic mass in the same group.

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When the forces on an object have a net force of zero ( the object is still or going constant speed ).
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the object is still

Explanation:

You need a stronger force than the opposing force to move an object.

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Explain how the lithosphere, hydrosphere, and atmosphere individually and collectively affect the biosphere. (2 points)
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The hydrosphere, the sphere of influence that deals with water in its various forms (some separate out ice and call that the cryosphere), provides the biosphere with a much needed component....water. Life would not exist as we know it without water. It places in important role for all organisms, alongside playing an important role in various earth processes.

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How long does it take a earth to rotate on its axis?
MissTica

Answer:

23 hours, 56 minutes about 24 hours

Explanation:

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You Discover A Beautiful Island Upon Which You May Build Your Own Society. You Make The Rules. What Is The First Rule You Put In
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Read 2 more answers
A 7450 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.35 m/s2 and feels no appreci
bagirrra123 [75]

Answer:

a) 520m

b) 10.30 s

c) 100,95 m/s

Explanation:

a) According the given information, the rocket suddenly stops when it reach the height of 520m, because the engines fail, and then it begins the free fall.

This means the maximum height this rocket reached before falling  was 520 m.

b) As we are dealing with constant acceleration (due gravity) g=9.8 \frac{m}{s^{2}} we can use the following formula:

y=y_{o}+V_{o} t-\frac{gt^{2}}{2}   (1)

Where:

y_{o}=520 m  is the initial height of the rocket (at the exact moment in which it stops due engines fail)

y=0  is the final height of the rocket (when it finally hits the launch pad)

V_{o}=0 is the initial velocity of the rocket (at the exact moment in which it stops the velocity is zero and then it begins to fall)

g=9.8m/s^{2}  is the acceleration due gravity

t is the time it takes to the rocket to hit the launch pad

Clearing t:

0=520 m+0-\frac{9.8m/s^{2} t^{2}}{2}   (2)

t^{2}=\frac{-520 m}{-4.9 m/s^{2}}   (3)

t=\sqrt{106.12 s^{2}   (4)

t=10.30 s   (5)  This is the time

c) Now we need to find the final velocity V_{f} for this rocket, and the following equation will be perfect to find it:

V_{f}=V_{o}-gt  (6)

V_{f}=0-(9.8 m/s^{2})(10.30 s)  (7)

V_{f}=-100.95 m/s  (8) This is the final velocity of the rocket. Note the negative sign indicates its direction is downwards (to the launch pad)

7 0
3 years ago
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