Answer:
the awnser should be. 165
F(x) = (x² - 3x - 10)(x + 4) becomes (x - 5)(x + 2)(x + 4) when completely factored. Now set each binomial equal to zero.
x - 5 = 0
x = 5
x + 2 = 0
x = - 2
x + 4 = 0
x = - 4
Your zeros are at x = - 4, - 2, and 5. Or at (- 4, 0), (- 2, 0), and (5, 0).
This may not be very pretty.
(2x + 5) * (2x + 5) expanded is (use foil)
F = 4x^2
O = 2x * 5 = 10x
I = 2x + 5 = 10x
L = 25
Total = 4x^2 + 20x + 25
(x + 3)(x + 3) = x^2 + 6x + 9 by the same method
(2x + 7)(2x + 7) = 4x^2 + 28x + 49 Same method.
4x^2 + 20x + 25 + x^2 + 6x + 9 = 4x^2 + 28x + 49
5x^2 + 26x + 34 = 4x^2 + 28x + 49 Collect everything on the left.
x^2 - 2x - 15 = 0
(x - 5)(x + 3) = 0
x + 3 will have no meaning.
x - 5 = 0
x = 5
2x + 5 = 2*5 + 5 = 15
x + 3 = 5 + 3 = 8
2x+ 7 = 2*5 +7 = 17
Check
15^2 + 8^2 = 17^2
225 + 64 = ? 289
289 = 289
a = 15 <<<<< answer
b = 8 <<<<< answer
c = 17 <<<<< answer
Answer:
Both plans are correct
Step-by-step explanation:
I already did it
Answer:
yes
Step-by-step explanation:
2x-4=6
Let x = 5
2*5 - 4 = 6
10 -4 =6
6 = 6
Since this is true, x=5 is a solution to the equation
