Find the perimeter for both questions. Both questions are compound shapes please provide working out.

Mathematics

1 answer:

Marrrta [24]3 years ago

8 0

First one:
You take 10 + 3 =13 then add 9 then 5. That all equals 27. Then you add 1 for the top part that isn’t labeled because it’s 10 in the bottom then 9 at the top which means it’s 1. Then for the side that’s unlabeled it’s 2 since it’s all 5 then the other side is 3. Answer is 31

Second one:

This one is the same as #1. You add 14+6+3+4 = 27. The long horizontal unlabeled side is 11 bc 14-3 = 11. Then the other side 2. Answer is 30.

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Solve for x x/6=10 1) x=10 2) x=60 3) x=4 4) x=16

gregori [183]

Answer:

2) x=60

Step-by-step explanation:

x/6=10

multiply both sides by 6

x = 10*6

x=60

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3 years ago

Read 2 more answers

Question and choices are in the photo please explain the answer

Natasha_Volkova [10]

Answer:

$\text{A) }68\:\mathrm{cm}$

Step-by-step explanation:

The perimeter of a polygon is equal to the sum of all the sides of the polygon. Quadrilateral PTOS consists of sides TP, SP, TO, and SO.

Since TO and SO are both radii of the circle, they must be equal. Thus, since TO is given as 10 cm, SO will also be 10 cm.

To find TP and SP, we can use the Pythagorean Theorem. Since they are tangents, they intersect the circle at a $90^{\circ}$ , creating right triangles $\triangle TOP$ and $\triangle SOP$ .