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2 years ago

Find the perimeter for both questions. Both questions are compound shapes please provide working out.

Mathematics

1 answer:

Marrrta [24]2 years ago

8 0

First one:
You take 10 + 3 =13 then add 9 then 5. That all equals 27. Then you add 1 for the top part that isn’t labeled because it’s 10 in the bottom then 9 at the top which means it’s 1. Then for the side that’s unlabeled it’s 2 since it’s all 5 then the other side is 3. Answer is 31

Second one:

This one is the same as #1. You add 14+6+3+4 = 27. The long horizontal unlabeled side is 11 bc 14-3 = 11. Then the other side 2. Answer is 30.

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WINSTONCH [101]

X 3 5
Y 6 10

ANSWER #3. .

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2 years ago

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3 (x+2)+9<6(x-3) solve the inequality and write the solution using interval notation

Darya [45]

Answer:

(11, ∞).

Step-by-step explanation:

3 (x+2)+9<6(x-3)

3x + 6 + 9 < 6x - 18

-3x < -18 - 6 - 9

-3x < -33

x > 11 (Note the inequality flips as we are dividing by a negative value).

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2 years ago

Simplify: (8^2)^3<br> please help:)

alexira [117]

Answer:

262144

Step-by-step explanation:

its exponents

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2 years ago

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Claire Judice

Julli [10]

Answer:

The values of 'x' are -1.2, 0, 0, $-4i$ or $4i$ .

Step-by-step explanation:

Given:

The equation to solve is given as:

$5x^5+6x^4+80x^3+96x^2=0$

Factoring $x^2$ from all the terms, we get:

$x^2(5x^3+6x^2+80x+96)=0$

Now, rearranging the terms, we get:

$x^2(5x^3+80x+6x^2+96)=0$

Now, factoring $5x$ from the first two terms and 6 from the last two terms, we get:

$x^2(5x(x^2+16)+6(x^2+16))=0\\x^2(x^2+16)(5x+6)=0$

Now, equating each factor to 0 and solving for 'x', we get:

$x^2=0\\x=0\ and\ 0\\\\5x+6=0\\x=\frac{-6}{5}=1.2\\\\x^2+16=0\\x^2=-16\\x=\sqrt{-16}=\pm 4i$

There are 3 real values and 2 imaginary values. The value of 'x' as 0 is repeated twice.

Therefore, the values of 'x' are -1.2, 0, 0, $-4i$ or $4i$ .

4 0

3 years ago

Please help !<br> If you can

iren2701 [21]

Answer:

80 degrees

Step-by-step explanation:

We can use the Central Angle Theorum, which states that if the vertex of the angle is the center of the circle, then the arc is the same measurement as the angle.

In this case, m<COB is 80 degrees, and the vertex is the center of the circle, which means that measure of arc CB is also 80 degrees

8 0

3 years ago