For what value of c will this function have one zero? f(x) = X^2 +c

1 answer:

6 0

X² + c is actually a quadratic function.

And x² + c = 0, it usually has two zeros which are solutions.

But for when c = 0,

x² + c = 0

x² + 0 = 0

x² = 0

Taking the square root of both sides.

x = 0. Here it only has one zero.

So the function x² + c, only has one root for c = 0.

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maw [93]

Answer:

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see the attached figure

Step-by-step explanation:

we have

$f(x)=x^{2}-2x-8$

we know that

The y-intercept is the value of the function f(x) when the value of x is equal to zero

For x=0

$f(x)=0^{2}-2(0)-8\\f(x)=-8$

therefore

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see the attached figure to better understand the problem

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