Solve this someone (1−4m)(m 2 −3m+8)

djverab [1.8K]

1. |b/5|=1 take the equation out of the absolute value
b/5=1
*5 *5 multiply both sides by 5
_____
b=5

2. 2-5|5m-5|=-73 get rid of what's outside the absolute value first
-2 -2 subtract 2 from both sides
____________
-5|5m-5|=-75
÷-5 ÷-5 divide both sides by -5
__________
|5m-5|=15 take the equation out of the absolute value
5m-5=15
+5 +5 add 5 to both sides
_______
5m=20
÷5 ÷5 divide both sides by 5
_____
m=4

3. |7p+4|/8=3
*8 *8 multiply by 8
__________
|7p+4|=25 take out the equation
7p+4=25
-4 -4 subtract 4
_______
7p=20
÷7 ÷7 divide by 7
______
p=20/7

4. 5-8|-2n|=-80
+5 +5 add 5
__________
-8|-2n|=-80
÷-8 ÷-8 divide by -8
________
|-2n|=10 take out equation
-2n=10
÷-2 ÷-2 divide by -2
______
n=-5

that took forever to type lol :^)

5 0

3 years ago

Graph the exponential function.

lara31 [8.8K]

Exponential Function doesn't have a graph that intercepts x-axis only if it is f(x) = a^x (when a>0 and a ≠ 1)

If you want to plot five points to graph the function then. I'd rather do from negative number to positive number.

Substitute from -3≤x≤1 (We get 5 points)

f(-3) = 4^-3

f(-3) = 1/4^3

f(-3) = 1/64 (First point) (-3,1/64)

f(-2) = 4^-2

f(-2) = 1/4^2 = 1/16 (Second point) (-2,1/16)

f(-1)=4^-1 = 1/4 (Third point) (-1, 1/4)

f(0) = 4^0 = 1 (Fourth point) (0, 1)

f(1) = 4^1 = 4 (Fifth point) (1,4)

4 0

3 years ago

Two kids at a summer camp, Antonio and Kenneth, are competing in a potato sack race. Antonio is younger, so he is given a head s

lara31 [8.8K]

Answer: 21m

Step-by-step explanation:

Kenneth will have to hop 21 meters.

6 0

3 years ago

Determine the time necessary for P dollars to double when it is invested at interest rate r compounded annually, monthly, daily,

Rudik [331]

Answer:

Part 1) 8.17 years

Part 2) 4.98 years

Part 3) 4.95 years

Part 4) 4.95 years

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part 1) Determine the time necessary for P dollars to double when it is invested at interest rate r=14% compounded annually

in this problem we have

$t=?\ years\\ P=\$p\\A=\$2p\\r=14\%=14/100=0.14\\n=1$

substitute in the formula above

$2p=p(1+\frac{0.14}{1})^{t}$

$2=(1.14)^{t}$

Apply log both sides

$log(2)=log[(1.14)^{t}]$

$log(2)=(t)log(1.14)$

$t=log(2)/log(1.14)$

$t=8.17\ years$

Part 2) Determine the time necessary for P dollars to double when it is invested at interest rate r=14% compounded monthly

in this problem we have

$t=?\ years\\ P=\$p\\A=\$2p\\r=14\%=14/100=0.14\\n=12$

substitute in the formula above

$2p=p(1+\frac{0.14}{12})^{12t}$

$2=(\frac{12.14}{12})^{12t}$

Apply log both sides

$log(2)=log[(\frac{12.14}{12})^{12t}]$

$log(2)=(12t)log(\frac{12.14}{12})$

$t=log(2)/12log(\frac{12.14}{12})$

$t=4.98\ years$

Part 3) Determine the time necessary for P dollars to double when it is invested at interest rate r=14% compounded daily

in this problem we have

$t=?\ years\\ P=\$p\\A=\$2p\\r=14\%=14/100=0.14\\n=365$

substitute in the formula above

$2p=p(1+\frac{0.14}{365})^{365t}$

$2=(\frac{365.14}{365})^{365t}$

Apply log both sides

$log(2)=log[(\frac{365.14}{365})^{365t}]$

$log(2)=(365t)log(\frac{365.14}{365})$

$t=log(2)/365log(\frac{365.14}{365})$

$t=4.95\ years$

Part 4) Determine the time necessary for P dollars to double when it is invested at interest rate r=14% continuously

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$t=?\ years\\ P=\$p\\A=\$2p\\r=14\%=14/100=0.14$

substitute in the formula above

$2p=p(e)^{0.14t}$

Simplify

$2=(e)^{0.14t}$

Apply ln both sides

$ln(2)=ln[(e)^{0.14t}]$

$ln(2)=(0.14t)ln(e)$

Remember that ln(e)=1

$ln(2)=(0.14t)$

$t=ln(2)/(0.14)$

$t=4.95\ years$

4 0

3 years ago

GIVING BRAINIEST!!! I NEED THE INEQUALITY SENTENCE FOR THIS!!!!!!!

forsale [732]

Answer:

Your bro/sis would have to weigh 35 lbs

Step-by-step explanation:

I did it wit a calculator!

5 0

3 years ago

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