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Gala2k [10]
2 years ago
13

Solve x^2 - x ≥ 0.

Mathematics
1 answer:
Cloud [144]2 years ago
5 0

Answer:

hhhhh

Step-by-step explanation:

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In Exercises 10 and 11, points B and D are points of tangency. Find the value(s) of x.<br>​
Lemur [1.5K]

In both cases,

AB^2=AD^2

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

(4x+7)^2=(6x-3)^2

16x^2+56x+49=36x^2-36x+9

20x^2-92x-40=0

5x^2-23x-10=0

(5x+2)(x-5)=0\implies\boxed{x=5}

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

(4x^2-18x-10)^2=(x^2+x+4)^2

16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16

15x^4-146x^3+235x^2+352x+84=0

(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}

(again, omit the solutions that would give a negative length for either AB or AD)

7 0
3 years ago
A line that includes the point (-11,-1) has a slope of 1. What is it's equation in slope intercept form.
Natali5045456 [20]

Answer:

y - 1 = 1( x -11)

Step-by-step explanation:

I hope this helps you out!

3 0
3 years ago
Kalani bought 2.5 pounds oranges for $1.58 per pound.how much did kalani spend on oranges ?
Tcecarenko [31]

To find the answer for this simply multiply 2.5 by 1.58

2.5 x 1.58= 3.95

So Kalani spent a total of $3.95 on oranges!

6 0
3 years ago
Read 2 more answers
What is the period of y=3cot(4x−3π)
Stells [14]
Hello!

hint: we can rewrite your function as below:

<span>3/<span>tan<span>(<span>4x−3π</span>) = </span></span></span>3(1+tan4xtan3π)/tan4x−tan3π = 

=<span>3/<span>tan<span>(<span>4x</span>) = </span></span></span>3cot<span>(<span>4x</span><span>)

</span></span>now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:

<span>"4P=π"


Hope this Helps! Have A Wonderful Day! :)</span>
4 0
3 years ago
Which of the following describes the number below? 0.92479247..
kykrilka [37]

Answer:

I believe its D.

Rational Only

Step-by-step explanation:

4 0
3 years ago
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