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valkas [14]
3 years ago
8

The graph below shows the function f(x)=x-3/x^2-2x-3 which statement is true

Mathematics
2 answers:
marishachu [46]3 years ago
7 0

Answer:

Its A. I just passed the final exam with 5 minutes left of the SESSION.

Step-by-step explanation:

Ugo [173]3 years ago
4 0

Answer:

The correct option is A.

Step-by-step explanation:

Domain:

The expression in the denominator is x^2-2x-3

x² - 2x-3 ≠0

-3 = +1 -4

(x²-2x+1)-4 ≠0

(x²-2x+1)=(x-1)²

(x-1)² - (2)² ≠0

∴a²-b² =(a-b)(a+b)

(x-1-2)(x-1+2) ≠0

(x-3)(x+1) ≠0

x≠3 for all x≠ -1

So there is a hole at x=3 and an asymptote at x= -1, so Option B is wrong

Asymptote:

x-3/x^2-2x-3

We know that denominator is equal to (x-3)(x+1)

x-3/(x-3)(x+1)

x-3 will be cancelled out by x-3

1/x+1

We have asymptote at x=-1 and hole at x=3, therefore the correct option is A....

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watch oreimo..

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2 years ago
The health club is raising money through a babysitting fundraiser. On Thursday, they charged $3 per hour plus an initial fee $40
xeze [42]

They need to babysit for 10 hours to have same money each day.

Step-by-step explanation:

On Thursday;

Charges = $3 per hour

Initial fee = $40

let x be the number of hours.

T(x) = 3x+40

On Friday;

Charges = $4 per hour

Initial fee = $30

F(x)= 4x+30

The cost will be same when;

T(x) = F(x)

3x+40=4x+30\\40-30=4x-3x\\10=x\\x=10

They need to babysit for 10 hours to have same money each day.

Keywords: functions, addition

Learn more about functions at:

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3 years ago
You run 1 3/4 miles each day. Your friend runs 4times as far as you do. How far does your friend run each day
Inga [223]
Just make 1 3/4 an improper fraction and multiply by 4:

1 3/4 = 7/4

7/4 * 4 = 7
7 0
3 years ago
Read 2 more answers
A building has an entry the shape of a parabolic arch 22 ft high and 28 ft wide at the base, as shown below.
Ivenika [448]
The parabola is at Max of 22
5 0
2 years ago
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bixtya [17]

The first equation given 6=1-2n+5

We have to add 1 and 5 to the right side first. We will get,

6= 6 - 2n

To get rid of 6 from the right side we have to subtract 6 from both sides.

6-6 = 6-6-2n

6-6 = -2n

0=-2n

To find n we have to move -2 to the other side by dividing both side by -2.

0/-2 = -2n/-2

0= n

n=0

So we have got the required answer for the first question.

The solution is n = 0.

The second equation given,

8x-2 = -9+7x

First we have to move 7x to the left side by subtracting it from both sides.

8x-7x-2 = -9+7x-7x

8x-7x-2 = -9

x-2 = -9

Now we have to move -2 to the right side by adding 2 to both sides.

x-2+2 = -9+2

x = -9+2

x = -7

We have got the required answer for the second question.

The solution is x = -7.

The third equation given,

-8 = -(x+4)

We have to get rid of that negative sign from both sides. As we have negative sign to both sides we can cancel it out. We will get,

8=x+4

Now we have to move 4 to left side by subtracting it from both sides.

8-4 = x+4-4

8-4 = x

4=x

x = 4

So we have got the required answer .

The solution is x = 4.

3 0
3 years ago
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