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valkas [14]
3 years ago
8

The graph below shows the function f(x)=x-3/x^2-2x-3 which statement is true

Mathematics
2 answers:
marishachu [46]3 years ago
7 0

Answer:

Its A. I just passed the final exam with 5 minutes left of the SESSION.

Step-by-step explanation:

Ugo [173]3 years ago
4 0

Answer:

The correct option is A.

Step-by-step explanation:

Domain:

The expression in the denominator is x^2-2x-3

x² - 2x-3 ≠0

-3 = +1 -4

(x²-2x+1)-4 ≠0

(x²-2x+1)=(x-1)²

(x-1)² - (2)² ≠0

∴a²-b² =(a-b)(a+b)

(x-1-2)(x-1+2) ≠0

(x-3)(x+1) ≠0

x≠3 for all x≠ -1

So there is a hole at x=3 and an asymptote at x= -1, so Option B is wrong

Asymptote:

x-3/x^2-2x-3

We know that denominator is equal to (x-3)(x+1)

x-3/(x-3)(x+1)

x-3 will be cancelled out by x-3

1/x+1

We have asymptote at x=-1 and hole at x=3, therefore the correct option is A....

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The answer is <span>10 units
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The diameter of the cylinder (d) is the twice of its radius (r): d = 2r

The volume (V) of the cylinder with radius r and height h is:
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We have:
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175π = π * r² * 7
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r² = 25
r = √25
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Why Did the Piano Player Bang Her
Sedbober [7]

The circumference of a circle that was computed when the diameter is 3cm will be 9.426cm.

<h3>How to find the circumference?</h3>

The circumference of a circle of gotten by the formula:

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