The graph below shows the function f(x)=x-3/x^2-2x-3 which statement is true
2 answers:
Answer:
Its A. I just passed the final exam with 5 minutes left of the SESSION.
Step-by-step explanation:
Answer:
The correct option is A.
Step-by-step explanation:
Domain:
The expression in the denominator is x^2-2x-3
x² - 2x-3 ≠0
-3 = +1 -4
(x²-2x+1)-4 ≠0
(x²-2x+1)=(x-1)²
(x-1)² - (2)² ≠0
∴a²-b² =(a-b)(a+b)
(x-1-2)(x-1+2) ≠0
(x-3)(x+1) ≠0
x≠3 for all x≠ -1
So there is a hole at x=3 and an asymptote at x= -1, so Option B is wrong
Asymptote:
x-3/x^2-2x-3
We know that denominator is equal to (x-3)(x+1)
x-3/(x-3)(x+1)
x-3 will be cancelled out by x-3
1/x+1
We have asymptote at x=-1 and hole at x=3, therefore the correct option is A....
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i think 3/5 but not 100%
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3 (a/3) = a
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a/3 + a/3 + a/3
3 times a/3
the 3's cancel each other out
A
Keep up the good work! =)
There should be 1.208 ounces of peanut butter in one serving. Since we are finding how many ounces in a serving, we divide from 30.2. 30.2 divided by 25 should be 1.208 ounces. :) I hope this helped
The answer is D, tony would always be behind Robert.
