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Sergio [31]
3 years ago
10

Can anyone help me choose the correct answer?!

Mathematics
1 answer:
lara [203]3 years ago
7 0

Answer:

f(x)=x-6 is your answer.

when x=0

f(0)=0-6=-6

similarly other too

You might be interested in
If 9x is an odd integer, represent the next odd integer as the algebraic expression in x.
Luba_88 [7]
Any odd integer can be expressed as 2n+1, for some integer n.

The next odd integer, after 2n+1, is 2n+1+2=2n+3



thus 9x=2n+1, means that 9x-1=2n,   so n=(9x-1)/2

the next odd number after 2n+1 is 2n+3= 2* (9x-1)/2+3=9x-1+3=9x+2


Remark : this result could also have been found directly.


Answer: 9x+2
8 0
4 years ago
Pls help it is due very soon.
WINSTONCH [101]

Answer:

Step-by-step explanation:

The Pythagorean theorem is sqrt(a^2 + b^ 2) = c, so:

sqrt(22^2 + 8^2) = c

sqrt(548) = c

23.41 = c

5 0
2 years ago
If you have 8 batteries cost $40 [cost per battery]
Finger [1]

Answer:

the answer is 5 because 40 divided by 8 is 5

5 0
3 years ago
Read 2 more answers
A self proclaimed psychic was tested for ESP. The psychic was presented with 200 cards face down and asked to determine if the c
swat32

Answer:

The 95% confidence interval would be given (0.172;0.288).  

We are confident at 95% that the true probability that the psychic correctly identifies the symbol on the card in a random trial is between (0.172;0.288).  

We can conclude that her random guessing would have got her correct 20% of the time. Since the confidence interval contains 0.2, she has no psychic powers, rather she just guessed it like normal people. Any person could have got it correct this many times.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Description in words of the parameter p

p represent the probability that the psychic correctly identifies the symbol on the card in a random trial

\hat p represent the estimated probability that the psychic correctly identifies the symbol on the card in a random trial

n=200 is the sample size required  

z_{\alpha/2} represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the cases successful

\hat p=\frac{46}{200}=0.23 represent the estimated probability that the psychic correctly identifies the symbol on the card in a random trial

Confidence interval

The confidence interval for a proportion is given by this formula:

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

And replacing into the confidence interval formula we got:  

0.23 - 1.96 \sqrt{\frac{0.23(1-0.23)}{200}}=0.172  

0.23 + 1.96 \sqrt{\frac{0.23(1-0.23)}{200}}=0.288  

And the 95% confidence interval would be given (0.172;0.288).

We are confident at 95% that the true probability that the psychic correctly identifies the symbol on the card in a random trial is between (0.172;0.288).  

We can conclude that her random guessing would have got her correct 20% of the time. Since the confidence interval contains 0.2, she has no psychic powers, rather she just guessed it like normal people. Any person could have got it correct this many times.

6 0
3 years ago
How do you write 0.63 as a fraction?​
tatuchka [14]

Hello!

Answer:

First, write 0.63 as 0.63/1

Then, multiply both numerator and denominator by 10 for every number after the decimal point.

0.63x100/1x100=63/100

so your answer is 63/100 :)

Hope this helps

7 0
2 years ago
Read 2 more answers
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