Write the expression in complete n^2(n+8)-4(n+8)

How to find equation of line passing through the points (x,y)

DochEvi [55]

First you must acknowledge that you are dealing with a line therefore you must write linear equation or linear function in this case.

Linear function has a form of,

$y=mx+n$

Then calculate the slope m using the coordinates of two points. Let say A(x1, y1) and B(x2, y2),

$m=\dfrac{\Delta{y}}{\Delta{x}}=\dfrac{y_2-y_1}{x_2-x_1}$

Now pick a point either A or B and insert coordinates of either one of them in the linear equation also insert the slope you just calculated, I will pick point A.

$y_1=mx_1+n$

From here you solve the equation for n,

$y_1=mx_1+n\Longrightarrow n=y_1-mx_1$

So you have slope m and variable n therefore you can write down the equation of the line,

$f(x)=m_{slope}x+n_{variable}$

Hope this helps.

r3t40

3 0

2 years ago

1. A bag of marbles has 15 marbles in it. there are 7 Red marbles and 8 Green marbles. What is the ratio probability of pulling

elixir [45]

Answer:

pulling red 7:15

green 8:15

54% chance of pulling green because 8 is 54% of 15

3 0

3 years ago

Read 2 more answers

What is the equation of the line that passes through the points (4/5,1/5) and (1/2,3/2)?

Setler [38]

Answer:

$y-\frac{3}{2}=\frac{-13}{3}(x-\frac{1}{2})$ point-slope form

$13x+3y=11$ (standard form)

Let me know if you prefer another form.

Step-by-step explanation:

The slope of a line can be found using $\frac{y_2-y_1}{x_2-x_1}$ provided you are given two points on the line.

We are.

Now you can use that formula. But I really love to just line up the points vertically then subtract them vertically then put 2nd difference over 1st difference.

(4/5 , 1/5)

-( 1/2 , 3/2)

-----------------

3/10 -13/10

2nd/1st = $\frac{\frac{-13}{10}}{\frac{3}{10}}=\frac{-13}{3}$ is our slope.

So the following is point-slope form for a linear equaiton:

$y-y_1=m(x-x_1) \text{ where } m \text{ is slope and } (x_1,y_1) \text{ is a point on the line }$

Plug in a point $(x_1,y_1)=(\frac{1}{2},\frac{3}{2}) \text{ and } m=\frac{-13}{3}$ .

This gives:

$y-\frac{3}{2}=\frac{-13}{3}(x-\frac{1}{2})$

I'm going to distribute:

$y-\frac{3}{2}=\frac{-13}{3}x-\frac{-13}{6}$

Now I don't like these fractions so I'm going to multiply both sides by the least common multiply of 2,3, and 6 which is 6:

$6y-9=-26x+13$

Add 26x on both sides:

$26x+6y-9=13$

Add 9 on both sides:

$26x+6y=22$ This is actually standard form of a line.

It can be simplified though.

Divide both sides by 2:

$13x+3y=11$ (standard form)

7 0

3 years ago

Read 2 more answers

Find the reciprocal (Urgent!!)

Mars2501 [29]

Answer:

1) 2

2) $\frac{3}{2}$ or $1\frac{1}{2}$

3) 5

4) 3

5) $\frac{5}{3}$ or $1\frac{2}{3}$

6) $\frac{4}{5}$

7) $\frac{5}{2}$ or $2\frac{1}{2}$

8) $\frac{7}{3}$ or $2\frac{1}{3}$

9) $\frac{2}{3}$

Step-by-step explanation:

The reciprocal is the fraction flipped. To make sure it is a reciprocal though, multiply the original and the reciprocal. If it is the correct reciprocal, you will get 1 as your answer.

Hope it helps!

3 0

3 years ago

For 12-15, find the missing measures

Bess [88]

12.

7, 14, 14pi, 7^2pi

13.

13, 26, 26pi, 13^2pi

14.

9, 18, 18pi, 9^2pi

15.

10, 20, 20pi, 10^2pi

4 0

3 years ago