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3 years ago

Let u = <-4, 1>, v = <-1, 6>. Find -2u + 4v

Mathematics

1 answer:

Maksim231197 [3]3 years ago

6 0

Answer:

<4,22>.

Step-by-step explanation:

This question involves the concepts of addition and scalar multiplication of vectors. It is given that the vector u = <-4, 1> and v = <-1, 6>. To find -2u, simply multiply -2 with the elements of u. This will give:

-2u = <-4*-2, 1*-2> = <8, -2>.

Similarly:

4v = <-1*4, 6*4> = <-4, 24>.

Hence,

-2u + 4v = <8, -2> + <-4, 24> = <8-4, -2+24> = <4,22>.

So the correct answer is <4,22>!!!

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If you are offered one slice from a round pizza (in other words, a sector of a circle) and the slice must have a perimeter of 24

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Answer:

A 12 in diameter will reward you with the largest slice of pizza.

Step-by-step explanation:

Let $r$ be the radius and $\theta$ be the angle of a circle.

According with the graph, the area of the sector is given by

$A=\frac{1}{2}r^2\theta$

The arc lenght of a circle with radius $r$ and angle $\theta$ is $r \theta$

The perimeter of the pizza slice is composed of two straight pieces, each of length r inches, and an arc of the circle which you know has length s = rθ inches. Thus the perimeter has length

$2r+r\theta=24 \:in$

We need to express the area as a function of one variable, to do this we use the above equation and we solve for $\theta$

$2r+r\theta=24\\r\theta=24-2r\\\theta=\frac{24-2r}{r}$

Next, we substitute this equation into the area equation

$A=\frac{1}{2}r^2(\frac{24-2r}{r})\\A=\frac{1}{2}r(24-2r)\\A=12r-r^2$

The domain of the area is

$0$

To find the diameter of pizza that will reward you with the largest slice you need to find the derivative of the area and set it equal to zero to find the critical points.

$\frac{d}{dr} A=\frac{d}{dr}(12r-r^2)\\A'(r)=\frac{d}{dr}(12r)-\frac{d}{dr}(r^2)\\A'(r)=12-2r$