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3 years ago

Let u = <-4, 1>, v = <-1, 6>. Find -2u + 4v

Mathematics

1 answer:

Maksim231197 [3]3 years ago

6 0

Answer:

<4,22>.

Step-by-step explanation:

This question involves the concepts of addition and scalar multiplication of vectors. It is given that the vector u = <-4, 1> and v = <-1, 6>. To find -2u, simply multiply -2 with the elements of u. This will give:

-2u = <-4*-2, 1*-2> = <8, -2>.

Similarly:

4v = <-1*4, 6*4> = <-4, 24>.

Hence,

-2u + 4v = <8, -2> + <-4, 24> = <8-4, -2+24> = <4,22>.

So the correct answer is <4,22>!!!

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The bus travels 35 blocks in 7 minutes . If the bus travels at a constant speed , how long will it take to travel 50 blocks ?

Mademuasel [1]

Answer:

10 min

Step-by-step explanation:

35/7=5 blocks in 1 min

50/5=10

6 0

2 years ago

Solve 7x2(x + 1) = 6x + 14<br> Ox=-12<br> Ox = 12<br> Ox= -16<br> Ox = 16

Evgen [1.6K]

$\large\displaystyle\text{$\begin{gathered}\sf 7x-2(x+1)=6x+4 \end{gathered}$}$

Use the distributive property to multiply −2 by x+1.

$\large\displaystyle\text{$\begin{gathered}\sf 7x-2x-2=6x+14 \end{gathered}$}$

Combine 7x and −2x to get 5x.

$\large\displaystyle\text{$\begin{gathered}\sf 5x-2=6x+14 \end{gathered}$}$

Subtract 6x on both sides.

$\large\displaystyle\text{$\begin{gathered}\sf 5x-2-6x=14 \end{gathered}$}$

Combine 5x and −6x to get −x.

$\large\displaystyle\text{$\begin{gathered}\sf -x-2=14 \end{gathered}$}$

Add 2 to both sides.

$\large\displaystyle\text{$\begin{gathered}\sf -x=14+2 \end{gathered}$}$

Add 14 and 2 to get 16.

$\large\displaystyle\text{$\begin{gathered}\sf -x=16 \end{gathered}$}$

Multiply both sides by −1.

$\large\displaystyle\text{$\begin{gathered}\sf x=-16 \ \ \to \ \ \ Answer \end{gathered}$}$

<h2>{ Pisces04 }</h2>

3 0

1 year ago

Read 2 more answers

How do you find the derivative of 1/logx?

valentina_108 [34]

The derivative of 1/logx is With the chain rule.

1log(x)=log(x)−1 is ,= -1xlog(x)2 .

The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".

The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.

$With the chain rule. \\ 1log(x)=log(x)−1 \\ So you follow the chain rule to the electricity after which to the log: \\ ddxlog(x)−1=−1⋅log(x) \\ \\−2⋅ddxlog(x) \\ =−1log(x)21x \\ =−1xlog(x)2 .$