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faust18 [17]
3 years ago
8

Solve the equation by completing the square x^2-10x+26=8​

Mathematics
2 answers:
irakobra [83]3 years ago
4 0

Answer:

x = 5 + sqrt(7) or x = 5 - sqrt(7)

Step-by-step explanation by completing the square:

Solve for x:

x^2 - 10 x + 26 = 8

Subtract 26 from both sides:

x^2 - 10 x = -18

Add 25 to both sides:

x^2 - 10 x + 25 = 7

Write the left hand side as a square:

(x - 5)^2 = 7

Take the square root of both sides:

x - 5 = sqrt(7) or x - 5 = -sqrt(7)

Add 5 to both sides:

x = 5 + sqrt(7) or x - 5 = -sqrt(7)

Add 5 to both sides:

Answer:  x = 5 + sqrt(7) or x = 5 - sqrt(7)

Natalka [10]3 years ago
3 0

Answer:

the answer is +/- 5 and the √7 for both. Put 5 where the "A's" are and 7 where the "B's" are

Step-by-step explanation:

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Solve for x. Write the smaller solution first, and the larger solution second.
vekshin1

Answer:

x=-4.73   x=-1.27

Step-by-step explanation:

(x + 3)^2 - 3 = 0

Add 3 to each side

(x + 3)^2 - 3 +3= 0+3

(x + 3)^2 = 3

Take the square root of each side

sqrt((x + 3)^2) =±sqrt( 3)

(x + 3) =±sqrt( 3)

Subtract 3 from each side

x + 3-3 =-3±sqrt( 3)

x = -3±sqrt( 3)

Approximating to 2 decimal places

x=-1.27 x=-4.73

6 0
3 years ago
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A circular table has a diameter of 20 inches.what is the area of the table
Effectus [21]
Hello!

To find the area of a circle you do \pi r ^{2}

the "r" stands for radius which is half the diameter

So we do \pi * 10^{2}

Which gives us the answer of 314.16

Hope this helps!
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3 years ago
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Use two fractions to write an expression with an estimated sum of 2
Ivenika [448]
Dear Mathee2, you can do 1/10+1 8/10≈2 and 1/20+1 19/20≈2. Note: you said fractions, so did you want the fractions to be mixed numbers or improper fractions?
5 0
3 years ago
I do not know how to solve this problem or know what to do with the exponents
horsena [70]
K, remember
(ab)/(cd)=(a/c)(b/d) or whatever
also
(ab)^c=(a^c)(b^c)
and
x^{-m}= \frac{1}{x^m}
and
x^ \frac{m}{n}= \sqrt[n]{x^m}
and
( \frac{x}{y} )^m= \frac{x^m}{y^m}
and
(x^m)^n=x^{mn}
and
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)


so
( \frac{-7x^ \frac{3}{2} }{5y^4} )^{-2}=
( \frac{-7}{5} )^{-2}( \frac{x^ \frac{3}{2} }{y^4} )^{-2}=
( \frac{(-7)^{-2}}{5^{-2}} )( \frac{(x^ \frac{3}{2})^{-2} }{(y^4)^{-2}} )=
( \frac{ \frac{1}{(-7)^2} }{ \frac{1}{5^2} } )( \frac{x^ \frac{-6}{2} }{y^{-8}} )=
( \frac{ \frac{1}{49} }{ \frac{1}{25} } )( \frac{(x^{-3}) }{\frac{1}{y^8}} )
( \frac{ \frac{1}{49} }{ \frac{1}{25} } )( \frac{\frac{1}{x^3} }{\frac{1}{y^8}} )=
(\frac{25}{49} )( \frac{y^8}{x^3}=
\frac{25y^8}{49x^3}
4 0
3 years ago
Divide<br> (-x* + 2x’ +3x– 5x – 2)/(x² – 2x+1)
nata0808 [166]

Answer:

3/4 ÷ 1/2

Step-by-step explanation:

5 0
3 years ago
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