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faust18 [17]
3 years ago
8

Solve the equation by completing the square x^2-10x+26=8​

Mathematics
2 answers:
irakobra [83]3 years ago
4 0

Answer:

x = 5 + sqrt(7) or x = 5 - sqrt(7)

Step-by-step explanation by completing the square:

Solve for x:

x^2 - 10 x + 26 = 8

Subtract 26 from both sides:

x^2 - 10 x = -18

Add 25 to both sides:

x^2 - 10 x + 25 = 7

Write the left hand side as a square:

(x - 5)^2 = 7

Take the square root of both sides:

x - 5 = sqrt(7) or x - 5 = -sqrt(7)

Add 5 to both sides:

x = 5 + sqrt(7) or x - 5 = -sqrt(7)

Add 5 to both sides:

Answer:  x = 5 + sqrt(7) or x = 5 - sqrt(7)

Natalka [10]3 years ago
3 0

Answer:

the answer is +/- 5 and the √7 for both. Put 5 where the "A's" are and 7 where the "B's" are

Step-by-step explanation:

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3 years ago
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irina [24]

Answer:

\boxed{-3(x+3)(x^2-6x+10)}

Step-by-step explanation:

Hello,

As the polynomial has only real coefficients, it means that 3-i is a zero too, because we apply the Conjugate Zeros Theorem.

It means that we can write the expression as below, k being a real number that we will have to identify.

k(x+3)(x-3-i)(x-3+i)=k(x+3)((x-3)^2-i^2)\\\\=k(x+3)(x^2-6x+9+1)\\\\=k(x+3)(x^2-6x+10)

And for x = 0, y = -90 so we can write

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Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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Step-by-step explanation:

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