All categories

2 years ago

What is BC ? Enter your answer in the box. BC= units

Mathematics

1 answer:

kumpel [21]2 years ago

5 0

Answer:

The length of BC is 25 units.

Step-by-step explanation:

We know that the triangle is an isosceles triangle. Hence, we know that AB = AC. Let's first solve for x.

=> 4x + 1 = 2x + 23
=> 4x - 2x = -1 + 23
=> 2x = 22
=> x = 11

Now, let's substitute the value into the expression.

=> 3x - 8
=> 3(11) - 8
=> 33 - 8
=> 25

Hence, the length of BC is 25 units.

Hoped this helped.

$BrainiacUser1357$

You might be interested in

There are 100 people in a wedding house, including children, men and women, and there are 100 pappadas to give with Sadya Te.

olga nikolaevna [1]

Answer:

Two possible sets of answers.

5 men, 11 women and 42 children, or

10 men, 2 women and 88 children

Selamat Sadhya!

Step-by-step explanation:

M = number of men

W = number of women

100-M-W = number of children

Total number of pappadas

5M+3W+(100-M-W)/2 = 100

Solve for W

W = (100-9M)/5 .......................(1)

Examine equation (1).

In order to have W as a whole number, M must be multiple of 5

Therefore M = 5 or 10

If M = 5, W = (100-45)/5 = 11 and children = 100-5-11 = 84

If M = 10, W = (100-90)/5 = 2 and children = 100-10-2 = 88

8 0

3 years ago

Y=f(x)=2x find f(x) when x=2

Rainbow [258]

Y=f(x)=2x find f(x) when x=2

Plug in

f(2)=2(2) =4

Answer

3 0

4 years ago

Read 2 more answers

If you were creating a lamp by hand what type of material would you choose for the wiring in what material would you choose to c

grin007 [14]

The material for the lamp of the wiring would be cutting with pliers.

8 0

3 years ago

Read 2 more answers

The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.

tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that perpendicular lines have negative reciprocal slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

$\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}$

so, it passes through the midpoint of AB,

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)$

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}$

4 0

3 years ago

= Drag up the correct symbol to make each statement true.

Dvinal [7]

Answer:

1. >

2.>

3.<

4. <

Step-by-step explanation:

I am doing it from top to bottom

I hope this helps! :)

4 0

3 years ago

What is ​ BC ​ ? Enter your answer in the box. BC= units

What is BC ? Enter your answer in the box. BC= units