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DENIUS [597]
3 years ago
6

Melissa launches a rocket from a 3-meter-tall platform. The height, h, of the rocket, in meters, can be modeled by the given gra

ph.
Melissa knows that h(1) = 23 meters and h(a) = 34.25 meters.

What is a reasonable estimate of the average rate of change of the height of the rocket, in meters per second, between a and b seconds? Explain your reasoning.

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
5 0
We can model the function between a and b as a linear function of negative slope because it is a short interval and the change is not very significant.
 We have then that the average rate of change in that interval is:
 m = (f (a) - f (b)) / (a-b)
 Substituting the values:
 m = (34.25 - 26) / (2.5-3.6)
 m = -7.5
 Negative, because the function decreases in that interval.
 Answer:
 a reasonable estimate of the average rate of change of the height of the rocket, in meters per second, between a and b seconds is:
 m = -7.5 m / s
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For z = –3 – 5i, which graph shows z and the product of z · i?
earnstyle [38]

Answer:

A

Step-by-step explanation:

z = -3 - 5i

z (i) = i (-3 - 5 i)

z (i) = -3i - 5i^2

z (i) = -3i - 5 (-1)

z (i) = -3i + 5

z (i) = 5 - 3i

Therefore, letter A is the correct answer.

3 0
3 years ago
(5×10 exponent 8)/(2×10 exponent 6)​
iogann1982 [59]
500,000,000 and 2,000,000

10 exponent 8 is 100000000 because it has 8 0s
multiply that by 5 to get 500,000,000

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3 0
3 years ago
Can someone please help
Rudiy27

It is B or 2. Hope this helps


6 0
3 years ago
How to solve this :') please help
blsea [12.9K]

Answer:

3/2

Step-by-step explanation:

sin(3π/4 - β) = sin(3π/4)cosβ - cos(3π/4)sinπ =

\sin(\frac{3\pi}{4}-\beta)=\sin(\frac{3\pi}{4})\cos\beta-\cos\frac{3\pi}{4}\sin\beta\\=\frac{1}{\sqrt{2}}\cos\beta-(-\frac{1}{\sqrt{2}})\sin\beta\\\\=\frac{1}{\sqrt{2}}(\cos\beta +\sin\beta)\\\\\sin^2(\frac{3\pi}{4}-\beta)=\frac{1}{2}\cos\beta +\sin\beta)^2=\frac{1}{2}(\cos^2\beta +\sin^2\beta+2\sin\beta\cos\beta\\=\frac{1}{2}(1+\sin2\beta)=\frac{1}{2}(1-\frac{1}{5}) = \frac{2}{5}\\

Use \cot^2x=\csc^2x-1=\frac{1}{\sin^2x}-1

so

\cot^2(\frac{3\pi}{4}-\beta)=\frac{1}{\sin^2(\frac{3\pi}{4}-\beta)}-1 = \frac{1}{\frac{2}{5}}-1=\frac{5}{2}-1=\frac{3}{2}

7 0
2 years ago
If sin(2x) = cos(x + 30"), what is the value of x?<br> 20°<br> 30°<br> 500<br> 1100
ivanzaharov [21]

Answer:

2x=(x+30)

2x+x=30

3x=30

x=30÷3

x=10

7 0
3 years ago
Read 2 more answers
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