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wlad13 [49]
2 years ago
15

Which number is an integer? -34 -0.4 0.4 3.4 PLS HELP I'M TIMED EDGE 2020

Mathematics
2 answers:
Stella [2.4K]2 years ago
7 0

Answer:

Step-by-step explanation:         The four numbers:  - 34, -0.4, 0.4, 3.4

so if you look at it it  The answer is -34

musickatia [10]2 years ago
3 0

Answer:

-34

Step-by-step explanation:

this is because an integer is a negative or positive whole number, and in this case, -0.4, 0.4 and 3.4 are decimal numbers

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For what values of x is f(x) = |x + 1| differentiable? I'm struggling my butt off for this course
pav-90 [236]

By definition of absolute value, you have

f(x) = |x+1| = \begin{cases}x+1&\text{if }x+1\ge0 \\ -(x+1)&\text{if }x+1

or more simply,

f(x) = \begin{cases}x+1&\text{if }x\ge-1\\-x-1&\text{if }x

On their own, each piece is differentiable over their respective domains, except at the point where they split off.

For <em>x</em> > -1, we have

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while for <em>x</em> < -1,

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More concisely,

f'(x) = \begin{cases}1&\text{if }x>-1\\-1&\text{if }x

Note the strict inequalities in the definition of <em>f '(x)</em>.

In order for <em>f(x)</em> to be differentiable at <em>x</em> = -1, the derivative <em>f '(x)</em> must be continuous at <em>x</em> = -1. But this is not the case, because the limits from either side of <em>x</em> = -1 for the derivative do not match:

\displaystyle \lim_{x\to-1^-}f'(x) = \lim_{x\to-1}(-1) = -1

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All this to say that <em>f(x)</em> is differentiable everywhere on its domain, <em>except</em> at the point <em>x</em> = -1.

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Step-by-step explanation:

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