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Marina CMI [18]
2 years ago
11

Find the distance from the point (1, 4) to the line y = 1/3x – 3.

Mathematics
1 answer:
Otrada [13]2 years ago
8 0

Answer: Distance between line and point =

4√5 -3/2√10

Step-by-step explanation:

Distance between the line is

= √ ((9-0)²+(0+1)²)

= √ (89+1)

= √90

= 3√10

Half of the line = 3/2√10

Distance of one side of the line and the point.

= √((9-1)²+(0-4)²)

= √((8)²+(-4)²)

=√64+16

= √80

= 4√5

Distance between line and point =

4√5 -3/2√10

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3 years ago
PLEASE HELP <br><br> y/7=x<br> what is y?
AlekseyPX

Answer:

You can't find y in this way

Step-by-step explanation:

You should know the value of x

But you can say

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5 0
2 years ago
Start at 7:30pm<br> add 46 minutes<br> add 20 minutes<br> add 53 minutes
mixer [17]

Answer:

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Step-by-step explanation:

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3 years ago
A tennis player moves in a straight-line path as shown in the figure below. find her average velocity in the following time inte
Andreyy89
To find the average velocity in a velocity-time graph at a particular interval, simply determine the gradient at that particular interval. 

<span>a. average velocity= 4/1 </span>
<span>= 4m/s </span>

<span>b. average velocity from 1 to 2.5s= 6/(2.5-1) </span>
<span>= 4m/s </span>

<span>average velocity from 2.5 to 4.0s= 0m/s </span>

<span>average velocity from 0 to 4.0s= (4+0)/4 </span>
<span>= 1m/s </span>

<span>c. average velocity from 1.0 to 4.0s= (4/3)m/s </span>

<span>average velocity from 4.0 to 5.0s= 2/1 </span>
<span>= 2.0m/s </span>

<span>average velocity from 1.0 to 5.0s= ((4/3)+2)/4 </span>
<span>= (5/6)m/s </span>

<span>d. average velocity from 0 to 4.0s= 1.0m/s </span>

<span>average velocity from 4.0 to 5.0s= 2.0m/s </span>

<span>average velocity from 0 to 5.0s= (1.0+2.0)/5 </span>
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4 0
3 years ago
Please solve for me!!
Allushta [10]

Answer:

A-base (s); three congruent rectangles.

5 0
3 years ago
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