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nexus9112 [7]
3 years ago
15

A spinner has three equally sized sections labeled from 1 to 3. The spinner is spun three times. How many outcomes are possible?

6 9 27 81
Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
7 0

Answer:  The correct option is (C) 27.

Step-by-step explanation:  Given that a spinner has three equally sized sections labeled from 1 to 3 and the spinner is spun three times.

We are to find the number of possible outcomes.

Since the spinner has three equally sized outcomes from 1 to 3, so

for each spun, there are 3 outcomes.

Given that the spinner has spun three times, so there will be 3 outcomes for each of the three spun.

Therefore, the total number of possible outcomes is given by

P_o=3\times 3\times 3=27.

Thus, the total number of possible outcomes is 27.

Option (C) is CORRECT.

GaryK [48]3 years ago
3 0
Counting principal
3 * 3 * 3 = 27 possibilities
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Find m angle TUV if m angle TUN=1+38 pi m angle NUV=66^ m angle TUV=105x
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Answer:

m∠TUV = 105

Step-by-step explanation:

From the question given above, the following data were obtained:

m∠TUN = 1 + 38x

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m∠TUV =?

Next, we shall determine the value of x. This can be obtained as illustrated below:

m∠TUV = m∠TUN + m∠NUV

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Divide both side by 67

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Read 2 more answers
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