<em><u>The solution is x = 8 and y = -5</u></em>
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
x + y = 3 ------ eqn 1
3x + 2y = 14 ------ eqn 2
We have to find the solution to the equations
We can use substitution method to solve
From eqn 1,
x + y = 3
Isolate for "x"
x = 3 - y ------ eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
3(3 - y) + 2y = 14
9 - 3y + 2y = 14
-y = 14 - 9
-y = 5
<h3>y = -5</h3>
<em><u>Substitute y = -5 in eqn 3</u></em>
x = 3 - (-5)
x = 3 + 5 = 8
<h3>x = 8</h3>
Thus the solution is x = 8 and y = -5
