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3 years ago

NEED HELP. LOOK AT PIC.

Mathematics

1 answer:

Sonja [21]3 years ago

8 0

Answer:

x = 8/3

y = 7/3

Step-by-step explanation:

In a parallelogram the diagonals bisect each other.

So 2x = y + 3

x + y = 5

Then you set them up to do combination/elimination to solve for the two variables.

2x-y = 3

Then you add the two equations together

3x = 8

Solve for x

x = 8/3

Then solve for y by plugging it into a equation

x + y = 5

8/3 + y = 5

8/3 - 5 = -y

8/3 - 15/3 = -y

-7/3 = -y

y = 7/3

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Divide using synthetic division (x^3+5x^2-x-5) divide (x+5)

Kamila [148]

Answer:

Quotient = x^ -1 and the remainder: 0

Step-by-step explanation:

Constant to the left with the opposite sign and coefficients to the right:

-5 | 1 5 -1 -5

Make an horizontal line

Bring down the first coefficient (1) under the line.

Multiply the constant -5 times 1=-5 and add -5 to 5 = 0

Keep doing the same with the coefficients.

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3 years ago

Let p and q be the propositions p: You drive over 65 miles per hour. q: You get a speeding ticket. Identify the expression that

natta225 [31]

Answer:

- p ⇒ - q

Step-by-step explanation:

p : Drive over 65 miles

q : You get a speeding ticket.

So then we get the negations.

- p : You do not drive over 65 miles

- q : You don't get a speeding ticket.

So, we need to connect the sentences. For that we use ⇒.

⇒ : then.

So, the sentence, If you do not drive over 65 miles per hour, then you will not get a speeding ticket

Can be written as : -p ⇒ -q

7 0

3 years ago

Can someone please help me with this math problem? Thank you!

lorasvet [3.4K]

To find the zeros, set y = 0
$-5(x-4)^2 +10 = 0$
Now try to isolate the (x-4)^2 term (move 10 to right side, divide by -5)
$(x-4)^2 = \frac{-10}{-5} = 2$
Next take square root of both sides (this cancels the square on (x-4))
$x-4 = \pm \sqrt{2}$
$x = 4 \pm \sqrt{2}$

For interpretation, x = price, y = profit
We are solving for price where profit = 0.

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4 years ago

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3 years ago

Read 2 more answers

During ski season,the owner of ski shop has determined that the number of customers in a day is greater then or equal to 50 more

Scilla [17]

The question is incomplete. Here is the complete question:

During ski season,the owner of ski shop has determined that the number of customers in a day is greater than or equal to 50 more then the temperature(Fahrenheit) . Write an inequality for the problem and determine the constraints on the variables.

Answer:

$N\geq T+50$

Step-by-step explanation:

Let the number of customers be 'N' and the temperature in Fahrenheit be 'T'.

Given:

Number of customers is related to temperature in Fahrenheit as:

Number of customers is greater than or equal to 50 more than the temperature in Fahrenheit. This means,

$N\geq T+50$

Now, since 'N' represents number of customers and number can never be a negative quantity. So, the only constraint for this inequality is that the number of customers must be greater than or equal to 0.

So, $N\geq 0$

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4 years ago