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slavikrds [6]
2 years ago
7

❗ANSWER+EXPLANATION=100POINTS+BRAINLIEST❗solve: (x+2)(5x-1)=0thanks)​

Mathematics
2 answers:
Sladkaya [172]2 years ago
6 0
<h3><u>Question</u><u>:</u><u>-</u></h3>

solve: (x+2)(5x-1)=0

<h3><u>Answer</u><u>:</u><u>-</u></h3>

x = 1/5

x = -2

<h3><u>Explanation</u><u>:</u><u>-</u></h3>

=> (x+2)(5x-1) = 0

=> x(5x-1) + 2(5x-1) = 0

=> 5x²- x + 10x - 2 = 0

=> 5x² + 9x - 2 = 0

  • Plug them into quadratic formula.

=> x = -9 ± √9²-4×5(-2) / 2×5 = -9 ± 11/10

  • To solve for the unknown variable, separate into two equations.... One with a plus and the other with a minus.

=> x = -9 + 11/10

=> x = -9 - 11/10

  • Rearrange and isolate variables and find each solution.

x = 1/5

x = -2

IrinaVladis [17]2 years ago
4 0

The solution to the given quadratic equation is;

x = -2 and x = 1/5

<h3>Roots of quadratic Equation </h3>

We are given the quadratic function;

(x + 2)(5x - 1) = 0

In quadratic functions, when it is expressed as;

(x + a)(x - b) = 0, what this means is that the factors of the quadratic equation or polynomial are; (x + a) and (x - b)

What that means is that the roots will be gotten from;

(x + a) = 0 and (x - b) = 0

Thus, applying the concept above on roots of a polynomial to our question, we have;

(x + 2) = 0 and 5x - 1 = 0

Solving them gives us;

x = -2 and x = 1/5

Read more on roots of quadratic equation at; brainly.com/question/8649555

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