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Hunter-Best [27]
4 years ago
12

Solve for y. 7y - 6y - 10 = 13

Mathematics
1 answer:
salantis [7]4 years ago
8 0
Start off by combining like terms (your y's).
7y - 6y - 10 = 13
y - 10 = 13

Now you need to get y by itself so add 10 to both sides

y - 10 = 13
+10       +10

y = 23
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saul85 [17]

\large\underline{\sf{Solution-}}

<u>Let us assume that:</u>

\sf \longmapsto x =  \sqrt{6 +  \sqrt{6 +  \sqrt{6 + ... \infty } } }

We can also write it as:

\sf \longmapsto x =  \sqrt{6 +  x }

Squaring both sides, we get:

\sf \longmapsto  {x}^{2}  =6 +  x

\sf \longmapsto  {x}^{2} - x - 6  =0

By splitting the middle term:

\sf \longmapsto  {x}^{2} - 3x + 2x - 6  =0

\sf \longmapsto x(x - 3) + 2(x - 3 ) =0

\sf \longmapsto (x+ 2)(x - 3 ) =0

<u>Therefore:</u>

\longmapsto\begin{cases} \sf (x+ 2) =0 \\ \sf (x - 3) = 0 \end{cases}

\sf \longmapsto x =  - 2,3

<u>But x cannot be negative. </u>

\sf \longmapsto x = 3

Therefore, the value of the expression is 3.

\large\underline{\sf{Verification-}}

Given:

\sf\longmapsto x=3

We can also write it as:

\sf\longmapsto x = \sqrt{9}

\sf\longmapsto x = \sqrt{6+3}

\sf\longmapsto x = \sqrt{6 + \sqrt{9}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+3}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{9}}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+3}}}

This pattern will continue.

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+...\infty}}}

7 0
3 years ago
Someone help me I dont get it ​
ioda

Answer:

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Step-by-step explanation:

let the price of a sandwich be $x.

entire order cost= cost of chips+ 5×cost of sandwiches

= 1.25 + 5x

1.25 + 5x = 38.75

5x=38.75-1.25

5x=37.50

x=7.50

7 0
3 years ago
Find the hcf of the following numbers <br>22,18​
Sergeu [11.5K]

Answer:

the required hcf is 2

okay

3 0
3 years ago
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Elena-2011 [213]

Answer:

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open the brackets

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if were solving for x:

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8 0
3 years ago
9.678 x 10^4<br> I am really stuck on scientific notation can someone help pls
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