Question

What is the product of (3a 2)(4a2 â€"" 2a 9)? 12a3 âÂ’ 2a 18 12a3 6a 9 12a3 âÂ’ 6a2 23a 18 12a3 2a2 23a 18.

Answer 1

The product of $(3a + 2)(4a^2 - 2a + 9)$ will be  $12a^3 + 2a^2 + 23a + 18.$

Given expression,

$(3a + 2)(4a^2 - 2a + 9).$

We have to find the product of $(3a + 2)(4a^2 - 2a + 9).$

Now using distributive property, we get

$3a(4a^2) - 3a(2a) + 3a(9) + 2(4a^2) - 2(2a) + 2(9)$

$12a^3 - 6a^2 + 27a + 8a^2 - 4a + 18$

$12a^3 + 2a^2 + 23a + 18$

 

Hence the product of $(3a + 2)(4a2 - 2a + 9)$  is $12a^3 + 2a^2 + 23a + 18.$

Thus the correct option is (D). $12a^3 + 2a^2 + 23a + 18.$

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