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IgorC [24]
3 years ago
6

1. 2y2 =1.44 please explain how i got my answer

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
5 0

2y^2=1.44\qquad\text{divide both sides by 2}\\\\y^2=\dfrac{1.44}{2}\to y=\pm\sqrt{\dfrac{1.44}{2}}\\\\y=-\dfrac{\sqrt{1.44}}{\sqrt2}\ \vee\ y=\dfrac{\sqrt{1.44}}{\sqrt2}\\\\y=-\dfrac{1.2}{\sqrt2}\ \vee\ y=\dfrac{1.2}{\sqrt2}\\\\y=-\dfrac{1.2\cdot\sqrt2}{\sqrt2\cdot\sqrt2}\ \vee\ y=\dfrac{1.2\cdot\sqrt2}{\sqrt2\cdot\sqrt2}\\\\y=-\dfrac{1.2\sqrt2}{2}\ \vee\ y=\dfrac{1.2\sqrt2}{2}\\\\\boxed{y=-0.6\sqrt2\ \vee\ y=0.6\sqrt2}

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3 0
3 years ago
20 + 23 - 34 + 2 x 4^2
olasank [31]
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8 0
4 years ago
(t^-4)^-9t^2 <br><br> A)t^26<br> B)t^-26<br> C)t^38<br> D)t^-38
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.. (t^a)^b = t^(a·b)
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4 0
3 years ago
Jerry says I've got my money in a great account that compounds interest monthly. The equation y=388 (1.008) represents how much
zheka24 [161]

Answer:

(a)His monthly Interest Rate=0.8%

(b)Annual Interest Rate = 9.6%

(c)500(1.008)^m

Step-by-step explanation:

For a Principal P invested at a yearly rate r, compounded m times in t years

Amount at Compound Interest= P(1+\frac{r}{m})^{mt}

Comparing with Jerry's equation y=388 (1.008)

(a)His monthly Interest Rate= 0.008=0.8%

(b)Annual Interest Rate= Monthly Interest Rate X 12 =0.8 X 12 = 9.6%

(c)If I invest $500 at the same rate of return,

Total Money after m months

= P(1+\frac{r}{m})^{mt}=500(1+0.008)^{m}=500(1.008)^m

7 0
4 years ago
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