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BlackZzzverrR [31]

3 years ago

5

How many ways are there to select 3 candidates from 8 equally qualified recent graduates for

1 answer:

kondaur [170]3 years ago

6 0

Step-by-step explanation:

How many ways are there to select 3 candidates from 8 equally qualified recent graduates for

openings in an accounting firm?

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5/10 = /6 is 5/10 and 3/6 equivalent fraction. if so, please explain

Sonja [21]

$\frac{5}{10}= \frac{1\cdot5}{2\cdot5} = \frac{1}{2} \ \ \ and\ \ \ \frac{3}{6}= \frac{1\cdot3}{2\cdot3} = \frac{1}{2} \ \ \ \ \Rightarrow\ \ \ \frac{5}{10}=\frac{3}{6}$

8 0

3 years ago

Please solve it and show a graph

vichka [17]

Answer: There is no photo it's just a black screen

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Pls help I don’t understand this question very well

kiruha [24]

Answer:

$CD = 12.6866616739cm$

$CD \approx12.7cm$

Step-by-step explanation:

$CB = a$

$AB = b$

$AC = c$

${c}^{2} = {a}^{2} + {b}^{2}$

${a}^{2} = {c}^{2} - {b}^{2}$

$a = \sqrt{ {c}^{2} - {b}^{2} }$

$a = \sqrt{ {12}^{2} - {6}^{2} }$

$a = \sqrt{144 - 36}$

$a = \sqrt{108}$

$CB = \sqrt{108}$

$\sin(D) = \frac{opposite}{hypotenuse}$

$\sin(D) = \frac{CB}{CD}$

$\sin(55) = \frac{ \sqrt{108} }{CD}$

$(CD) \sin(55) = \frac{ \sqrt{108} }{CD} (CD)$

$(CD) \sin(55) = \sqrt{108}$

$\frac{(CD) \sin(55) }{ \sin(55) } = \frac{ \sqrt{108} }{ \sin(55) }$

$CD = \frac{ \sqrt{108} }{ \sin(55) }$

$CD = 12.6866616739cm$

$CD \approx12.7cm$

6 0

3 years ago

If two angles are both obtuse, the two angles are equal. What is the converse??

asambeis [7]

Answer:

If the angles are equal, then two angles are both obtuse

Step-by-step explanation:

converse flips the conclusion and hypothesis

5 0

3 years ago

If ab = 9 and a² + b² = 81, then (a+b)² = ?

Andre45 [30]

Answer:

99

Step-by-step explanation:

Through some clever algebra, we can combine our first two equations using the fact that

$(a+b)^2=a^2+2ab+b^2$

We have the a² and the b² in the equation $a^2+b^2=81$ , and we <em>almost </em>have a 2ab in the equation $ab=9$ . To get that 2ab, we can simply double both sides of the first equation to get $2ab=18$ . From there, we'll add the first two equations together, giving us the summed equation

$a^2+b^2+2ab=81+18\\a^2+2ab+b^2=99$

And since $(a+b)^2=a^2+2ab+b^2$ , we can equivalently say that

$(a+b)^2=99$

5 0

3 years ago