As a fraction, it would be 5 6/10. Then you multiply the denominator by the whole number 5x10 and add the numerator. So,
10X5+6=56
56/10
divide by 2
28/5 is the simplified version
Step-by-step explanation:
1/5x+60=2/3x-2
subtract 1/5x from 2/3x
when you do that you should get 0.46x repeating
then you add two to 60
you should get 62
62=0.46x
divide x
you get 134.7
4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
Answer:
I believe it would be 4/6
Step-by-step explanation:
You have four different ways to get a sum of 7: 1 and 6; 2 and 5; 3 and 4; or 4 and 3.
That's 21.
Hope this helps !
Nyway
