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shtirl [24]
3 years ago
9

A new operation is defined by a△b=a^2-b/b-a^2 I HAVE A BRAINLIEST TO GIVE OUT!

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
8 0

Step-by-step explanation:

a = 5

b = -3

25 - -3/ -3 - 25

= 28 / -28

= -1

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11Alexandr11 [23.1K]

5 1/4-3 5/6=1 5/12

Hope this helped!!! :P

7 0
3 years ago
Misaki cut some wood for a bookcase she is building.She needs to find how many 1
den301095 [7]

Answer:

3ft + 2ft?

Step-by-step explanation:

sorry i would take this with a bucket of salt its prob not c0rr3t

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=9%5C%3A%20%20%5C%3A%20%20%5Cfrac%7B%20%5Csin%28%20%5Ctheta%29%20%7D%7B1%20%2B%20%20%5Ccos%28%2
PIT_PIT [208]

Option (b) is your correct answer.

Step-by-step explanation:

\large\underline{\sf{Solution-}}

Given Trigonometric expression is

\rm :\longmapsto\:\dfrac{sin\theta }{1 + cos\theta }

So, on rationalizing the denominator, we get

\rm \:  =  \: \dfrac{sin\theta }{1 + cos\theta }  \times \dfrac{1 - cos\theta }{1 - cos\theta }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) =  {x}^{2} -  {y}^{2} \: }}}

So, using this, we get

\rm \:  =  \: \dfrac{sin\theta (1  -  cos\theta )}{1 -  {cos}^{2}\theta  }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {sin}^{2}x +  {cos}^{2}x = 1}}}

So, using this identity, we get

\rm \:  =  \: \dfrac{sin\theta (1 -  cos\theta )}{{sin}^{2}\theta  }

\rm \:  =  \: \dfrac{1 - cos\theta }{sin\theta }

<u>Hence, </u>

\\ \red{\rm\implies \:\boxed{\tt{ \rm \:\dfrac{sin\theta }{1 + cos\theta }   =  \: \dfrac{1 - cos\theta }{sin\theta } }}} \\

3 0
3 years ago
Read 2 more answers
Ur wrong its acutully 39.8 not 39.75 u came up with the wrong answer.
alukav5142 [94]
It is 39.8 your right
3 0
4 years ago
I need help, please?
Drupady [299]

x is timed by .5 in the first one (A) which would make it the linear function.

6 0
3 years ago
Read 2 more answers
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